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True [87]
3 years ago
9

Find the median, Q1, Q3, the IQR for the following

Mathematics
2 answers:
zheka24 [161]3 years ago
7 0
<span>First, you would normally need to order the numbers from least to greatest, but since the numbers are already in order we can skip this step.

</span><span>24,24,28,32,40,42

</span><span>The median is the data value in the middle of the data set or, in this case because there is an even number of values, the average of the two middle values.

Median: 30

The first quartile value is the median for the numbers before the median.
So find the median of</span><span> 24, 24, 28, which is just the middle number.

First quartile: 24

Finding the third quartile is exactly the same as the first, except use the values after the median. (</span><span>32, 40, 42)

Third quartile: 40

The IQR (Inter-quartile Range) is just the the third quartile minus the first quartile.

40 - 24 = 16
</span>
<span>So here are your answers

Median: 30
</span><span>First quartile: 24</span>
Third quartile: 40
Inter-quartile range: 16


Let me know if you need help understanding anything and I'll try to explain as best I can.

Hope this helps!!

ELEN [110]3 years ago
4 0
<span>24,24,28, 32,40,42
median = (28+32)/2 = 30
Q1 = 24
Q3 = 40
IQR = 40 -24 = 16</span>
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1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t
natta225 [31]

The area of the surface given by \vec r_1(u,v) is 1. In terms of a surface integral, we have

1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv

By multiplying each component in \vec r_1 by 5, we have

\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}

and the same goes for the derivative with respect to v. Then the area of the surface given by \vec r_2(u,v) is

\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}

8 0
3 years ago
Can anyone help me solve this?
xxMikexx [17]

Answer:

a- 16/100

b- 1/6

c- not sure

Step-by-step explanation:

8 0
3 years ago
Plssss helpppp ASAPP<br> will mark BRAINLIEST!!!
ra1l [238]

Answer:

4th and 5th option

Step-by-step explanation:

you can easily add eqn 1 and 2 to get rid of the y term for 4th option and get rid of x term by addition as well for the 5th option

this is a topic on simultaneous equation. If you wish to explore more into this topic you can give me a follow on Instagram (learntionary) I'll be posting the notes for this topic and some other tips :)

5 0
3 years ago
Read 2 more answers
Can someone give me the answer and explanation I’ll give brainlist and points
victus00 [196]
This picture will explain the mistake. She didn’t carry down the -2/4 and add to make sure her answer was fully correct.

6 0
3 years ago
WILL MARK U AS BRAINLIEST PLZ HELP
Radda [10]

Answer:

112 if you don't include the triangle sides as they are not necessary, but 124 if you include one triangle and 136 if you include both triangle sides

5 0
3 years ago
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