The rate of change of the distance from the particle to the origin at this instant is 3 units per second.
<h3>What is the rate of change?</h3>
The instantaneous rate of change is the rate of change at a particular instant.
A particle is moving along the curve
The rate of change of y is given as:
dy / dx = 2
by differentiating both sides,
From the question, we have:
(x, y) = (5,24)
Substitute 5 for x and dy / dx = 2
Hence, the rate of change of the distance from the particle to the origin at this instant is 3 units per second.
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Answer:
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Step-by-step explanation:
5.C
6.D
I hope you get it correct
You are given two points in the linear function. At time 0 years, the value is $3000. At time 4 years, the value is $250. This means you have points (0, 3000) and (4, 250). You need to find the equation of the line that passes through those two points.
y = mx + b
m = (y2 - y1)/(x2 - x1) = (3000 - 250)/(0 - 4) = 2750/(-4) = -687.5
Use point (0, 3000).
3000 = -687.5(0) + b
b = 3000
The equation is
y = -687.5x + 3000
Since we are using points (t, v) instead of (x, y), we have:
v = -687.5t + 3000
Answer: d. v = -687.50 t + 3,000
