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IgorC [24]
3 years ago
8

If u help me then i will love you forever

Mathematics
1 answer:
Darina [25.2K]3 years ago
7 0

ok what do u need help with I don't see anything

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Write down the first three terms of the sequence whose nth term is given by 2n-5
likoan [24]

Answer:

- 3, - 1, 1

Step-by-step explanation:

To find the first 3 terms substitute n = 1, 2, 3 into the formula

a₁ = 2(1) - 5 = 2 - 5 = - 3

a₂ = 2(2) - 5 = 4 - 5 = - 1

a₃ = 2(3) - 5 = 6 - 5 = 1

The first 3 terms are - 3, - 1, 1

6 0
3 years ago
For A I somehow got 41.05 but its 2.95cm can someone show me the working and what I did wrong?
777dan777 [17]

Answer:

Step-by-step explanation:

a). tan(75°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

                  = \frac{11}{k}

    k = \frac{11}{\text{tan}(75)}

    k = 2.947

    k = 2.95 cm

b). cos(52°) = \frac{16}{s}

    s = \frac{16}{\text{cos}(52)}

    s = 25.988

    s ≈ 25.99 cm

c). sin(5°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

               = \frac{16.1}{q}

    q = \frac{16.1}{\text{sin}(5)}

    q = 184.727

    q ≈ 184.73 cm

4 0
2 years ago
Find the points on the ellipse 4x2 + y2 = 4 that are farthest away from the point (−1, 0).
Hitman42 [59]
<span>The two points that are most distant from (-1,0) are exactly (1/3, 4sqrt(2)/3) and (1/3, -4sqrt(2)/3) approximately (0.3333333, 1.885618) and (0.3333333, -1.885618) Rewriting to express Y as a function of X, we get 4x^2 + y^2 = 4 y^2 = 4 - 4x^2 y = +/- sqrt(4 - 4x^2) So that indicates that the range of values for X is -1 to 1. Also the range of values for Y is from -2 to 2. Additionally, the ellipse is centered upon the origin and is symmetrical to both the X and Y axis. So let's just look at the positive Y values and upon finding the maximum distance, simply reflect that point across the X axis. So y = sqrt(4-4x^2) distance is sqrt((x + 1)^2 + sqrt(4-4x^2)^2) =sqrt(x^2 + 2x + 1 + 4 - 4x^2) =sqrt(-3x^2 + 2x + 5) And to simplify things, the maximum distance will also have the maximum squared distance, so square the equation, giving -3x^2 + 2x + 5 Now the maximum will happen where the first derivative is equal to 0, so calculate the first derivative. d = -3x^2 + 2x + 5 d' = -6x + 2 And set d' to 0 and solve for x, so 0 = -6x + 2 -2 = -6x 1/3 = x So the furthest point will be where X = 1/3. Calculate those points using (1) above. y = +/- sqrt(4 - 4x^2) y = +/- sqrt(4 - 4(1/3)^2) y = +/- sqrt(4 - 4(1/9)) y = +/- sqrt(4 - 4/9) y = +/- sqrt(3 5/9) y = +/- sqrt(32)/sqrt(9) y = +/- 4sqrt(2)/3 y is approximately +/- 1.885618</span>
7 0
3 years ago
Help please :( 4^5 x 4^ -7 divide by 4^ -2 ?
alexandr1967 [171]

Answer:

4⁻⁴

Step-by-step explanation:

4⁵ × 4⁻⁷ ÷ 4⁻²

⁺ ⁵ ⁻ ⁷

= ⁻²

⁻ ² ⁻ ²

= ⁻ ⁴

4⁻⁴

7 0
3 years ago
Solve for x by completing the square: x2 - 12x + 11 = 0
sineoko [7]

Answer:

B

Step-by-step explanation:

x² - 12x + 11 = 0 ( subtract 11 from both sides )

x² - 12x = - 11

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(- 6)x + 36 = - 11 + 36

(x - 6)² = 25 ( take square root of both sides )

x - 6 = ± \sqrt{25} = ± 5 ( add 6 to both sides )

x = 6 ± 5

Then

x = 6 - 5 = 1 ⇒ (1, 0 )

x = 6 + 5 = 11 ⇒ (11, 0 )

6 0
2 years ago
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