Please help me with the math please?

Mathematics

2 answers:

Oxana [17]2 years ago

8 0

Answer:

count how many flowers there are on number 1

andre [41]2 years ago

4 0

Answer:

okay so 3. equals 20

4. 1st one 2nd one 3rd one equals 30

5. first one 2nd one 3rd one equals 30

6. first one second one equals 20

7. first one second one equals 20

Step-by-step explanation:

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Dae-Hyun drew a picture of a cruise ship that he saw docked at Port Canaveral. He used the scale shown below.

madreJ [45]

Answer: 592

Step-by-step explanation:

I did the test and i got it right :)

4 0

2 years ago

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0

2 years ago

1. Find the area of the shaded area of this figure:

statuscvo [17]

(area of square) - (area of triangle)

We know the are of a square is equal to s^2, where s is the side length.

While the are of a right angle tringle is 1/2*base*height

Then we have,

s = 10
base = 4
height = 4

(area of square) - (area of triangle)

=> (10^2) - (1/2)(4)(4)
=> 100 - 8
=> 92

Finally we get: 92 in^2

8 0

1 year ago

Someone please help im so dumb

34kurt

You are not alone I am dumb too

8 0

2 years ago

15. How would .89 be put as a fraction?

NikAS [45]

Answer:

0.89 as a fraction would equal: $\frac{117}{500}$