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dusya [7]
3 years ago
7

A density of solid 13g/cm³ at a temperature of 25°c was now heated to a temperature of 150°c find the new density of the solid ?

Given linear expansivity to be 2 × 10⁻⁵ ?​
Physics
1 answer:
nirvana33 [79]3 years ago
3 0

Answer:

13.4225 g/cm³

Explanation:

Given that:

Linear expansivity α = 2 * 10^-5

Change in temperature dt = t2 - t1 = (150 - 25)°c = 125°c

Initial density (d1) = 13

New density d2 =?

Using the relation :

α = (d2 - d1) / d1 * dt

d2 - d1 = d1 * dt * α

d2 = d1 + d1*dt*α

d2 = d1(1 + d1*dt*α)

d2 = 13( 1 + (13*125*2*10^-5))

d2 = 13(1 + 0.0325)

d2 = 13(1.0325)

d2 = 13.4225

d2 = 13.4225 g/cm³

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Explanation:

We can use Coulomb's law to find out the force, in scalar form, will be:

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we can find:

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Not so big for everyday life, but enormous for subatomic particles.

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The work done by the turbine will be 708.2 kJ/kg. The work done by the turbine is the difference of the enthalpy at inlet and exit.

<h3 /><h3>What is temperature?</h3>

Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.

If the given turbine is assumed to be reversible;

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\rm P_e (Exit pressure)=600 kpa=6 bar

The heat balance equation is;

\rm q-W_t=h_e-h_i\\\\ q=0\\\\\ W_t=h_i-h_e

The change in the entropy is;

\rm S_2-S_1=\frac{\delta q}{dt}

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brainly.com/question/7510619

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6 0
2 years ago
what are the speeds of (a) a proton that is accelerated from rest through a potential difference of −1000 v−1000 v and (b) an el
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1 year ago
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Answer:

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Now we have to find the work done

We know that work done is given by

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