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erik [133]
3 years ago
12

The filament of a certain lamp has a resistance that increases linearly with temperature. When a constant voltage is switched on

, the initial current decreases until the filament reaches its steady-state temperature. The temperature coefficient of resistivity of the filament is 43 times 10^-3 K^-1. The final current through the filament is one- eighth the initial current. What is the change in temperature of the filament?
a.30100 K
b.378 K
c.1627 K
d.814 K
e.1162 K
Physics
1 answer:
Neporo4naja [7]3 years ago
5 0

Answer:

162.8 K

Explanation:

initial current = io

final current, i = io/8

Let the potential difference is V.

coefficient of resistivity, α = 43 x 10^-3 /K

Let the resistance is R and the final resistance is Ro.

The resistance varies with temperature

R = Ro ( 1 + α ΔT)

V/i = V/io (1 + α ΔT )

8 = 1 + 43 x 10^-3 x ΔT

7 = 43 x 10^-3 x ΔT

ΔT = 162.8 K

Thus, the rise in temperature is 162.8 K.

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19 m/s

Explanation:

The complete question requires the final speed to be calculated.

Velocity is the rate and direction at which an object moves. Acceleration is the rate of change of velocity per unit time and can be calculated by the difference in velocity over a given time.

For this question, first the unknown acceleration must be calculated and used to determine the final velocity

Step 1: Calculate the acceleration

a=\frac{v_{2}-v{1}}{t_{1}}

a=\frac{11-7}{8}

a=\frac{4}{8}

a=0.5 m/s^{2}

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3 years ago
Galileo held that measurements of time were _____ and that measurements of distance were ______. absolute; relative
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the correct answer is option A

The given blanks in the question will be filled with Absolute and relative receptively.

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Read 2 more answers
Nuclear decay occurs according to first-order kinetics. How long will it take for a sample of radon-218 to decay from 99 grams t
dedylja [7]

It will take 267 milliseconds for a sample of radon-218 to decay from 99 grams to 0. 50 grams.

We know that half life of a first order reaction is given by: t_{1/2} = 0.693/k

where k = rate of reaction

Given half life = 35 milliseconds

So from this we get k = 0.0198

Now we know that rate of first order reaction is given by: kt= 2.303 * log(R'/R)

where t= time

R'= initial amount = 99 g

R= final amount= 0.50 g

k= rate of reaction = 0.0198

Putting values of these in above equation we get t=267 milliseconds.

i.e. It will take 267 milliseconds for a sample of radon-218 to decay from 99 grams to 0. 50 grams.

To know more about radioactivity visit:

brainly.com/question/20039004

#SPJ4

4 0
2 years ago
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