The specific heat of mercury is 149.4 J/(kgK)
Explanation:
When a substance is supplied with an amount of energy Q, its temperature increases according to the equation:
where
is the increase in temperature
m is the mass of the sample
is its specific heat capacity
For the sample of mercury in this problem we have
Q = 275 J
m = 0.450 kg
Therefore, by re-arranging the equation we find the mercury's specific heat:
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The question is missing a diagram of the ray reflection. I attached a diagram which comes from a similar question in the answer section. The full question should be as follows:
Two plane mirrors intersect at right angles. A laser beam strikes the first of them at a point d = 10.0cmfrom their point of intersection, as shown in the figure. For what angle of incidence at the first mirror will this ray strike the midpoint of the second mirror (which is s=29.0cm long) after reflecting from the first mirror?
Answer:
34.6°
Explanation:
To strike the midpoint of the second mirror, the ray light will have to travel half of the distance vertically
i.e. 29/2 = 14.5
We can solve this through trigonometry.
Let the angle between the ray and the vertical plane mirror is known as α
tan α = 10/14.5
α = = 34.6°
The angle of incidence is the angle between the ray and the normal line of the mirror.
Let angle of incidence of first mirror be β
β = α = 34.6
The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.
<h3>What mass of lead should be placed on the cube?</h3>
Given: Side of the cube (a) = 20cm
The density of the cube (ρc) =
a) Applying the force balance, the buoyant force must be equal to the weight of the cube
ρcgV = ρg × (Ax)
Substituting the values in the above equation, we get
x = 0.13
where x is the height of the cube in the water
is the area of the cross-section
ρ is the density of the water
V is the volume of the cube
Now, the height above the surface of the water would be
h = a − x
Substituting the values, then we get
h = 0.2 − 0.13
h = 0.07 m
b) The mass added is "m" so the complete cube is submerged in the water, therefore
ρcgV + mg = ρg × (V)
m = 2.8 kg
The mass added is "m" so the complete cube is submerged in the water is 2.8 kg.
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