Answer:
considering the 90both should be 45° each
We know that the intensity of light decreases as the square of the distance
from the source.
Lamp-1 is twice (2x) as far from the detector as Lamp-2 is.
If they appear equal to the detector, then Lamp-1 must be (2)² = 4 times
as bright as Lamp-2.
4 x 15 candelas = 60 candelas
Question #15).
A). is true, but has nothing to do with particle behavior
B). Diffraction is a purely wave thing, so it doesn't help.
C). is true, but doesn't say anything about particle behavior
D). is true, but isn't an indication of particle behavior.
Looks to me like NONE of the choices is any help
to suggest particle behavior.
Answer:
12353 V m⁻¹ = 12.4 kV m⁻¹
Explanation:
Electric field between the plates of the parallel plate capacitor depends on the potential difference across the plates and their distance of separation.Potential difference across the plates V over the distance between the plates gives the electric field between the plates. Potential difference is the amount of work done per unit charge and is given here as 21 V. Electric field is the voltage over distance.
E = V ÷ d = 21 ÷ 0.0017 = 12353 V m⁻¹
Answer: False
Explanation: In order to explain this problem we have to use the Faraday law, which say
dФm/dt=-ε it means that the variation of the magnetic field flux with time is equal to the emf ( electromotive force). In our case the magnetic flux is constant then there is not a emf induced in a wire closed loop.
