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3 years ago

What is the pOH value when the solutions hydroxide concentration is 1.0 x 10−6 M?

Chemistry

1 answer:

ikadub [295]3 years ago

5 0

Answer:

I think is B -8

Explanation:

I don't know but I think so

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How many molecules are there in 45.0 grams of CH ?

Sonbull [250]

Answer:

There are 1.8021 ⋅ 1024 molecules of CH4 in 48 grams of CH4. To answer this question, you must understand how to convert grams of a molecule into the number of molecules. To do this, you have to utilize the concepts of moles and molar mass. A mole is just a unit of measurement. Avogadro's number is equal to 6.022 ⋅1023 molecules/mole. i think please dont complain to me if its wrong im sorry

Explanation:

8 0

2 years ago

Balance the following equation in acidic conditions. Phases are optional. Cu NO3,

Gwar [14]

If your equation is Cu+NO^- 3-->Cu^2+NO, then the answer is
2 Cu + 1 NO3{-} → 1 Cu^{2+} + 3 NO

To check if it is balance, this is the solution:
2- Cu- 2
3- N -3
3- O -3

5 0

3 years ago

Under standard-state conditions, which of the following species is the best reducing agent? a. Ag+ b. Pb c. H2 d. Ag e. Mg2+

eimsori [14]

Answer: The correct answer is Option b.

Explanation:

Reducing agents are defined as the agents which help the other substance to get reduced and itself gets oxidized. They undergo oxidation reaction.

$X\rightarrow X^{n+}+ne^-$

For determination of reducing agents, we will look at the oxidation potentials of the substance. Oxidation potentials can be determined by reversing the standard reduction potentials.

For the given options:

Option a: $Ag^+$

This ion cannot be further oxidized because +1 is the most stable oxidation state of silver.

Option b: $Pb$

This metal can easily get oxidized to $Pb^{2+}$ ion and the standard oxidation potential for this is 0.13 V

$Pb\rightarrow Pb^{2+}+2e^-;E^o_{(Pb/Pb^{2+})}=+0.13V$

Option c: $H_2$

This metal can easily get oxidized to $H^{+}$ ion and the standard oxidation potential for this is 0.0 V

$H_2\rightarrow 2H^++2e^-;E^o_{(H_2/H^{+})}=0.0V$

Option d: $Ag$

This metal can easily get oxidized to $Ag^{+}$ ion and the standard oxidation potential for this is -0.80 V

$Ag\rightarrow Ag^{+}+e^-;E^o_{(Ag/Ag^{+})}=-0.80V$

Option e: $Mg^{2+}$

This ion cannot be further oxidized because +2 is the most stable oxidation state of magnesium.

By looking at the standard oxidation potential of the substances, the substance having highest positive $E^o$ potential will always get oxidized and will undergo oxidation reaction. Thus, considered as strong reducing agent.

From the above values, the correct answer is Option b.

8 0

3 years ago

Help with this question I don’t get it I will give out 30 points!!!

mina [271]

It has to be A or B bc c and d are just dumb answers

8 0

3 years ago

G vinegar is a solution of acetic acid in water. if a 165 ml bottle of distilled vinegar contains 28.2 ml of acetic acid, what i

Delicious77 [7]

Volume Percent (volume/volume%) is defined to be the ratio of the volume of solute to the volume of solution times 100%. The acetic acid is the solute volume. The bottle of vinegar is the solution volume. Acetic acid (28.2ml) / Vinegar(165ml) x 100% = 17.1%

7 0

3 years ago