The mass of hydrogen atoms that is measured at 54 u given the relationship is 89.64×10¯²⁴ g
<h3>Conversion scale </h3>
1 u = 1.66×10¯²⁴ g
<h3>How to determine the mass of hydrogen atoms </h3>
- Mass of Hydrogen (u) = 54 u
- Mass of Hydrogen (g) =?
1 u = 1.66×10¯²⁴ g
Therefore
54 u = 54 × 1.66×10¯²⁴ g
54 u = 89.64×10¯²⁴ g
Thus, the mass of the hydrogen atoms measured at 54 u is 89.64×10¯²⁴ g
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Answer:
The correct answer is - 4.
Explanation:
As we known and also given that the total of the superscripts that is mass numbers, A in the reactants and products must be the same.The mass of products A can understand and calculated by this -
The sum of the product mass number of products = mass of reactant
237Np93 →233 Pa91 +AZX is the equation,
Solution:
Mass of reactants = 237
Mass of products are - Pa =233 and A = ?
233 + A = 237
A = 237 - 233
A = 4
So the equation will be:
237Np93 →233 Pa91 +4He2 (atomic number Z = 2 ∵ difference in the atomic number of reactant and products)
Answer:
Answers are given below
Explanation:
(a) Aldehyde groups are reduced by sodium borohydride in methanol to give alcohol.
So, butanal produces butanol on reaction with sodium borohydride in methanol.
(b) Aldehyde forms cyanohydrin when they are treated with HCN with catalytic cyanide.
(c) Aldehydes are oxidized by potassium dichromate in dil. sulphuric acid to produce carboxylic acid.
(d) Aldehyde produces acetal with methanol and a trace amount of acid catalyst.
(e) Aldehyde gives condensation reaction with 
to produce imine.
Structures of products for the given reaction has been shown below.
Answer: nebula
Explanation: All stars start off in a large cloud of dust and gas which is called a nebula.
Explanation:
aluminium belongs to group 13 and period 3
