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e-lub [12.9K]
2 years ago
15

How many moles in 28.0 grams of Oxygen

Chemistry
1 answer:
anastassius [24]2 years ago
3 0

Answer:

1.) 28.0 grams of oxygen28 grams (1 mole/16 grams per mole)=1.75 moles oxygen2.)5.0 moles of Iron5 moles(55.845 grams/1 mole)=279.225 grams Iron3.) 452 grams Argon452 grams(1 mole/39.948 grams)=11.315 moles Argon4.) 16.5 moles Hydrogen16.5 moles(1.01 grams/1 mole)=16.665 grams Hydrogen

Explanation:

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WILL GIVE BRAINIEST ANSWER A chemical equation has different numbers of atoms on the left and right sides.
Alinara [238K]

Answer:

Unbalanced

Explanation:

You need to have the same number of atoms on both sides for it to be balanced

4 0
1 year ago
Chemical weathering processes do not alter the chemical structure of minerals in rocks. *
Anna007 [38]
I THINK that that is true. It's just weathering the rock down not change composition. Lemme know if you get it right please! (:
4 0
3 years ago
Thallium consists of 29.5%Th-203 and 70.5%Th-205. What is the relative atomic mass of thallium?
grin007 [14]
0.295 * 203 = 53.885
0.705 * 205 = 144.525
53.885 + 144.525 = 204.41
The relative atomic mass of Thallium is 204.41 
7 0
3 years ago
Read 2 more answers
The balanced equation for a hypothetical reaction is a + 5b + 6c → 3d + 3e. what is the rate law for this reaction? rate = k [a]
nekit [7.7K]

<u>Answer: </u>The correct rate of the reaction is Rate=k[a][b]^5[c]^6

<u>Explanation:</u>

Rate law of the reaction is the expression which expresses the rate of the reaction in the terms of the molar concentrations of the reactants with each term raised to the power of their respective stoichiometric coefficients in a balanced chemical equation.

For the given reaction:

a+5b+6c\rightarrow 3d+3e

The expression for the rate law will be: Rate=k[a][b]^5[c]^6

7 0
3 years ago
A student is instructed to make 1 L of a 2.0 M solution of CaCl2 using dry salt. How should he do this?
Pachacha [2.7K]
<span>The student should follow following steps to make 1 L of </span>2.0 M CaCl₂.<span>
<span>
1. First he should calculate the number of moles of 2.0 M CaCl</span></span>₂ in 1 L solution.<span>

</span>Molarity of the solution = 2.0 M<span>
Volume of solution which should be prepared = 1 L

Molarity = number of moles / volume of the solution

Hence, number of moles in 1 L = 2 mol

2. Find out the mass of dry CaCl</span>₂ in 2 moles.<span>

moles = mass / molar mass

Moles of CaCl₂ = 2 mol</span><span>
Molar mass of CaCl₂ = </span><span>110.98 g/mol

Hence, mass of CaCl</span>₂ = 2 mol x <span>110.98 g/mol
                                     = 221.96 g

3. Weigh the mass accurately 

4. Then take a cleaned and dry1 L volumetric flask and place a funnel top of it. Then carefully add the salt into the volumetric flask and finally wash the funnel and watch glass with de-ionized water. That water also should be added into the volumetric flask.

5. Then add some de-ionized water into the volumetric flask and swirl well until all salt are dissolved.

<span>6. Then top up to mark of the volumetric flask carefully. 
</span>
</span>
7. As the final step prepared solution should be labelled.
4 0
3 years ago
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