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3 years ago

Which box and whisker plot represents this data: 6,7,8,10,18,20,22,25,28,28,30,30?

Mathematics

2 answers:

kari74 [83]3 years ago

7 0

Answer:

its the last one D

Step-by-step explanation:

The median is 22 and the rest dont have that as the median

Juli2301 [7.4K]3 years ago

5 0

Um the same period that the time was not supposed to be the first one ☝ the time to get on the

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At East Middle School, there are 585858 left-handed students and 609609609 right-handed students. The numbers of left- and right

lisabon 2012 [21]

Answer: C. Left-handed: 48 Right-handed: 504

E. Left-handed: 30 Right-handed: 315

Step-by-step explanation:

Here is the completed question:

At East Middle School, there are 58 left-handed students and 609 right-handed students. The numbers of left- and right-handed students at West Junior High are proportional to the numbers at East Middle School. Which of the following could be the numbers of left-handed and right-handed students at West Junior High?

A. Left-handed: 42 Right-handed: 483

B. Left-handed: 28 Right-handed: 378

C. Left-handed: 48 Right-handed: 504

D. Left-handed: 56 Right-handed: 560

E. Left-handed: 30 Right-handed: 315

Since it's direct proportion, we have to calculate the constant of proportionality which will simply be:

= 609 / 58 = 10.5

A. Left-handed: 42 Right-handed: 483

Constant = 483/42 = 11.5

Incorrect

B. Left-handed: 28 Right-handed: 378

Constant = 378/28 = 13.5

Incorrect

C. Left-handed: 48 Right-handed: 504

Constant = 504/48 = 10.5

Correct

D. Left-handed: 56 Right-handed: 560

Constant = 560/56 = 10

Incorrect

E. Left-handed: 30 Right-handed: 315

Constant = 315/30 = 10.5

Correct

Therefore, the correct options are C and E.

3 0

2 years ago

Read 2 more answers

Before the distribution of certain statistical software, every fourth compact disk (CD) is testedfor accuracy. The testing proce

pishuonlain [190]

Answer:

P(T∩E) = 0.017

Step-by-step explanation:

Since every fourth CD is tested. Thus if T is the event that represents 4 disks being tested,

P(T) = 1/4 = 0.25

Let Fi represent event of failure rate. So from the question,

P(F1) = 0.01 ; P(F2) = 0.03 ; P(F3) =0.02 ; P(F4) = 0.01

Also Let F'i represent event of success rate. And we have;

P(F'1) = 1 - 0.01 = 0.99 ; P(F'2) = 1 - 0.03 = 0.97; P(F'3) = 1 - 0.02 = 0.98; P(F'4) = 1 - 0.01 = 0.99

Since all programs run independently, the probability that all programs will run successfully is;

P(All programs to run successfully) =

P(F'1) x P(F'2) x P(F'3) x P(F'4) =

0.99 x 0.97 x 0.98 x 0.97 = 0.932

Now, that all 4 programs failed will be = 1 - 0.932 = 0.068

Let E be denote that the CD fails the test. Thus P(E) = 0.068

Now, since testing and CD's defection are independent events, the probability that one CD was tested and failed will be =P(T∩E) = P(T) x P(E)= 0.25 x 0.068 = 0.017

8 0

3 years ago

Given: P is a point on the perpendicular bisector, I of MN.<br> Prove: PM = PN

Hatshy [7]

Answer:

Step-by-step explanation:

I can't make specific statements about the proof because the midpoint is missing.

Givens

There are two right angles created by where the perpendicular bisector meats MN. Both are 90 degrees.

MN is bisected by the point on MN where the perpendicular meets MN

The Perpendicular Bisector is is common to both triangles.

Therefore the two triangles are congruent by SAS

PM = PN Parts contained in Congruent triangles are congruent.

5 0

3 years ago

Find the measures of the interior angles.

Zina [86]

Answer:

x=41 degrees

c=90 degrees

Step-by-step explanation:

please give branliest i hope this helps

3 0

3 years ago

Solve for c: c - 12 = 3

vlabodo [156]

Steps to solve:

c - 12 = 3

~Add 12 to both sides

c = 15

Best of Luck!

8 0

3 years ago

Read 2 more answers