All categories

2 years ago

What is the final amount if 660 is increased by 1% followed by a further 1% increase? Give your answer rounded to 2 DP.

Mathematics

1 answer:

Delvig [45]2 years ago

3 0

Answer:

$673.27

Step-by-step explanation:

Initial amount = $660

1% Increase = $660*(1+1%)

1% Increase = $660+$6.6

1% Increase = $666.6

Further 1% Increase = $666.6*(1+1%)

Further 1% Increase = $666.6 + $6.666

Further 1% Increase = $673.266

Further 1% Increase = $673.27

You might be interested in

A hot air balloon was at a height of 2180 feet It designated at a rate of 150 feet per minute for 6 minutes. Find it’s height

OleMash [197]

2,180 - 150 • m

2,180- 150 • 6 =
2180- 900=m
1280=m

3 0

3 years ago

write the equation in slope-intercept form of the line that has a slope of -3 and contains the point (4, -5).

Novosadov [1.4K]

You can answer this question by plugging the given values into point-slope form, which is y - y_{1} = m (x - x_{1}). M will represent slope and x_{1} and y_{1} will represent the x and y coordinates.

y - y_{1} = m (x - x_{1}) Substitute in the values
y - (-5) = 4 (m - 4) Cancel out the -(-5)
y + 5 = 4 (m - 4) Use the Distributive Property
y + 5 = 4m - 16 Subtract 5 from both sides

y = 4m - 21

3 0

3 years ago

Find the area of this parallelogram. Be sure to include the correct unit in your answer.

DedPeter [7]

19 yards maybe i dont know

7 0

3 years ago

Read 2 more answers

The paint used to make lines on roads must reflect enough light to be clearly visible at night. Let µ denote the true average re

Zolol [24]

Answer:

a) $df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

b) $df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

c) $df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

$\bar X$ represent the sample mean

$s$ represent the standard deviation for the sample

$n$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to determine if the true mean is higher than 20, the system of hypothesis would be:

Null hypothesis: $\mu \leq 20$

Alternative hypothesis: $\mu > 20$

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

(a) n = 16, t = 3.3, a = 0.05, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=16-1=15$

The statistic calculated is given by t=3.3

Since is a one-side upper test the p value would be:

$p_v =P(t_{15}>3.3)=0.0024$

So since the p value is lower than the significance level $pv$ we reject the null hypothesis.

(b) n = 8, t = 1.8, a = 0.01, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=8-1=7$

The statistic calculated is given by t=1.8

Since is a one-side upper test the p value would be:

$p_v =P(t_{7}>1.8)=0.057$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

(c) n = 26,t = -0.6, P-value =

First we need to calculate the degrees of freedom given by:

$df=n-1=26-1=25$

The statistic calculated is given by t=-0.6

Since is a one-side upper test the p value would be:

$p_v =P(t_{25}>-0.6)=0.723$

So since the p value is higher than the significance level $pv>\alpha$ we FAIL to reject the null hypothesis.

3 0

3 years ago

Enter the missing numbers in the boxes to complete the table of equivalent ratios. Time (min) Distance (km) ?6 6 18 24 ? 15 ?

-BARSIC- [3]

Answer:

17ebook.co

Step-by-step explanation:

8 0

3 years ago