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statuscvo [17]
2 years ago
13

What is the final amount if 660 is increased by 1% followed by a further 1% increase? Give your answer rounded to 2 DP.

Mathematics
1 answer:
Delvig [45]2 years ago
3 0

Answer:

$673.27

Step-by-step explanation:

Initial amount = $660

1% Increase = $660*(1+1%)

1% Increase = $660+$6.6

1% Increase = $666.6

Further 1% Increase = $666.6*(1+1%)

Further 1% Increase = $666.6 + $6.666

Further 1% Increase = $673.266

Further 1% Increase = $673.27

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Can someone show me the steps to doing this ?
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3 years ago
3 determine the highest real root of f (x) = x3− 6x2 + 11x − 6.1: (a) graphically. (b) using the newton-raphson method (three it
Juliette [100K]

(a) See the first attachment for a graph. This graphing calculator displays roots to 3 decimal places. (The third attachment shows a different graphing calculator and 10 significant digits.)

(b) In the table of the first attachment, the column headed by g(x) gives iterations of Newton's Method. (For Newton's method, it is convenient to let the calculator's derivative function compute the derivative f'(x) of the function f(x). We have defined g(x) = x - f(x)/f'(x).) The result of the 3rd iteration is ...

... x ≈ 3.0473167

(c) The function h(x₁, x₂) computes iterations using the secant method. The results for three iterations of that method are shown below the table in the attachment. The result of the 3rd iteration is ...

... x ≈ 3.2291234

(d) The function h(x, x+0.01) computes the modified secant method as required by the problem statement. The result of the 3rd iteration is ...

... x ≈ 3.0477377

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... x ≈ 3.0466805180

_____

<em>Comment on these methods</em>

Newton's method can have convergence problems if the starting point is not sufficiently close to the root. A graphing calculator that gives a 3-digit approximation (or better) can help avoid this issue. For the calculator used here, the output of "g(x)" is computed even as the input is typed, so one can simply copy the function output to the input to get a 12-significant digit approximation of the root as fast as you can type it.

The "modified" secant method is a variation of the secant method that does not require two values of the function to start with. Instead, it uses a value of x that is "close" to the one given. For our purpose here, we can use the same h(x1, x2) for both methods, with a different x2 for the modified method.

We have defined h(x1, x2) = x1 - f(x1)(f(x1)-f(x2))/(x1 -x2).

6 0
2 years ago
Order six and three tenths repeating, negative six and four ninths, 630%, and −6.1 from least to greatest.
NNADVOKAT [17]

The order of six and three tenths repeating, negative six and four ninths, 630%, and −6.1 from least to greatest is negative six and four ninths, −6.1, 630%, six and three tenths repeating. option D

<h3>Ascending order</h3>

This is the arrangements of numbers from the least to the greatest, that is, from lower value to higher value.

six and three tenths repeating

= 6.333

negative six and four ninths

= -6 4/9

= -6.444

630%

= 630/100

= 6.3

−6.1

From least to greatest:

  • negative six and four ninths
  • −6.1
  • 630%
  • six and three tenths repeating

Therefore, the order six and three tenths repeating, negative six and four ninths, 630%, and −6.1 from least to greatest is negative six and four ninths, −6.1, 630%, six and three tenths repeating. option D

Learn more about ascending order:

brainly.com/question/12783355

#SPJ1

4 0
1 year ago
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