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My name is Ann [436]
3 years ago
10

Determine the intercepts of the line. 7x-5=4y-67x−5=4y−67, x, minus, 5, equals, 4, y, minus, 6 xxx-intercept: \Big((left parenth

esis ,,comma \Big))right parenthesis yyy-intercept: \Big((left parenthesis ,,comma \Big))
Mathematics
2 answers:
Fiesta28 [93]3 years ago
5 0

Answer:

x intercept: (-1/7 , 0)

y intercept: (0, 1/4)

Step-by-step explanation:

sesenic [268]3 years ago
4 0

Given:

The equation of line is

7x-5=4y-6

To find:

The x and y-intercept of the given line.

Solution:

We have,

7x-5=4y-6

Putting x=0, we get

7(0)-5=4y-6

Add 6 on both sides.

0-5+6=4y

1=4y

Divide both sides by 4.

\dfrac{1}{4}=y

So, the y-intercept is \left(0,\dfrac{1}{4}\right).

Putting y=0 in given equation, we get

7x-5=4(0)-6

Add 5 on both sides.

7x=-6+5

7x=-1

Divide both sides by 7.

x=\dfrac{-1}{7}

So, the x-intercept is \left(-\dfrac{1}{7},0\right).

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