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Advocard [28]
3 years ago
7

15 point question

Mathematics
1 answer:
Advocard [28]3 years ago
6 0

Answer:

The new pressure P₂  is 3.3 atm

Step-by-step explanation:

Pressure of gas = 2.7 atm

Volume = 3.6 L

Temperature = 324 K

Now we are given that  volume of the gas is kept constant.

Temperature is increased to 396 K

We need to find the pressure.

The formula used is: \frac{P_1}{T_1}=\frac{P_2}{T_2}

We have P₁ = 2.7

T₁ = 324 K

T₂ = 396 K

P₂ = ?

Putting values in the formula and finding P₂

\frac{P_1}{T_1}=\frac{P_2}{T_2}\\\frac{2.7}{324}=\frac{P_2}{396}\\P_2=\frac{2.7}{324}\times 396\\P_2=0.0083 \times 396\\P_2=3.3

So, the new pressure P₂  is 3.3 atm

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Solve for x −9x+5≤17 OR 13x+25≤−1
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Answer:

(-∞ 2] ∪ [-4/3 ∞ )

Step-by-step explanation:

Given compound inequality,

-9x+5\leq 17\text{ or }13x+25\leq -1

-9x\leq 12\text{ or }13x\leq -26  ( Subtraction property of inequality )

-x\leq \frac{12}{9}\text{ or }x\leq -\frac{26}{13}   ( Division property of inequality )

-x\leq \frac{4}{3}\text{ or }x\leq -2

x\geq -\frac{4}{3}\text{ or }x\leq -2   ( a < b ⇒ - a > - b )

Hence, the solution of the given inequality is,

(-∞ -2] ∪ [-4/3 ∞ )

3 0
3 years ago
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50 POINTS <br>NO LINKS <br>WILL MARK BRAINLYEST ​
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The equation is 7=1x and answer x=7
5 0
3 years ago
Increase #500 in the ratio 16:10
Oxana [17]

Answer:

Answer is <em>900</em>.

Step-by-step explanation:

To find:

Increase #500 in the ratio 16:10

Solution:

<em>New Number: Old Number = 16:10</em>

We are given the old number as 500.

Let the new number after increase = x

Now, using the above ratio:

<em />x<em>: </em>500<em> = </em>16:10

\dfrac{x}{500} = \dfrac{16}{10}\\\Rightarrow x = 500 \times \dfrac{16}{10}\\\Rightarrow x = 50 \times 16\\\Rightarrow x = 900

Therefore, the increased value of 500 in the ration 16:10 is <em>900</em>.

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3 years ago
Solve each system of equations.<br><br> 4x + 6y = 8<br> 5x – 4y = 25
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\left \{ {{y= -1\frac{28}{92} } \atop {x=5-\frac{96}{92} }} \right. \\  \left \{ {{y= -1\frac{7}{23} } \atop {x=5-1\frac{1}{23} }} \right. \\   \left \{ {{y= -1\frac{7}{23} } \atop {x=4\frac{1}{23} }} \right. \\
\boxed{(x; y)=(4\frac{1}{23}; -1\frac{7}{23}) }





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The quantity is called the pooled variance estimate of the common variance of two unknown but equal population variances. It is
lozanna [386]

Answer:

sample variances

Step-by-step explanation:

The pooled variance method is used to estimate the variance of several different population with different means, but are assume to have the same variance.

The weights represent the sample variances.

So the correct answer is

sample variances

5 0
3 years ago
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