Answer:
$17
Step-by-step explanation:
data:
- $139
- $136
- <u>$130 </u>
- $136
- <u>$147 </u>
- $136
In statistics, the range is the difference between the highest value and the lowest value of the data set.
Highest value = $147
Lowest value = $130
Range = $17
check the picture below. So the parabola looks more or less like so.
bearing in mind that the distance "p" is the same from the vertex to the directrix or the focus point, so the vertex is therefore half-way between those two fellows, now, from 3,4 up to y = 8, there are 4 units, and the vertex is half-way, thus is at y = 6, and x = 3, (3, 6) as you see there in the picture.
the parabola is vertical, meaning the squared variable is the "x", and is opening downwards, meaning the "p" distance is negative, so since "p" is 2 units, then p = -2.
![\bf \textit{parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=3\\ k=6\\ p=-2 \end{cases}\implies 4(-2)(y-6)=(x-3)^2\implies -8(y-6)=(x-3)^2 \\\\\\ y-6=\cfrac{(x-3)^2}{-8}\implies \blacktriangleright y=-\cfrac{1}{8}(x-3)^2+6 \blacktriangleleft](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bparabola%20vertex%20form%20with%20focus%20point%20distance%7D%0A%5C%5C%5C%5C%0A4p%28y-%20k%29%3D%28x-%20h%29%5E2%0A%5Cqquad%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Avertex%5C%20%28%20h%2C%20k%29%5C%5C%5C%5C%20p%3D%5Ctextit%7Bdistance%20from%20vertex%20to%20%7D%5C%5C%0A%5Cqquad%20%5Ctextit%7B%20focus%20or%20directrix%7D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5B-0.35em%5D%0A%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%0A%5Cbegin%7Bcases%7D%0Ah%3D3%5C%5C%0Ak%3D6%5C%5C%0Ap%3D-2%0A%5Cend%7Bcases%7D%5Cimplies%204%28-2%29%28y-6%29%3D%28x-3%29%5E2%5Cimplies%20-8%28y-6%29%3D%28x-3%29%5E2%0A%5C%5C%5C%5C%5C%5C%0Ay-6%3D%5Ccfrac%7B%28x-3%29%5E2%7D%7B-8%7D%5Cimplies%20%5Cblacktriangleright%20y%3D-%5Ccfrac%7B1%7D%7B8%7D%28x-3%29%5E2%2B6%20%5Cblacktriangleleft)
Standard form is an²+bn+c
expand
distribute
2n(3-n)+5=
2n(3)+2n(-n)+5=
6n-2n²+5=
-2n²+6n+5
g(n)=-2n²+6n+5 is standard form
Answer:
Coordinates of M = (2, -1)
Length of AB = 10 units
Step-by-step explanation:
Coordinates of the midpoint (M) of the distance between A(2, 4) and B(2, -6)

Let 

Thus:



Length of AB:
Distance between A(2, 4) and B(2, -6):

Let,




