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Olin [163]
3 years ago
12

50 ft 48 ft x ft Find x

Mathematics
2 answers:
Marizza181 [45]3 years ago
7 0

Answer:

Can you give more info.?

Step-by-step explanation:

Sophie [7]3 years ago
3 0
Not info pls !!!!! Then I can help
You might be interested in
At an university 70% of the students who attend stay on campus. If 1,380 of the students who attend live off campus, what is the
Alborosie

Answer:

4600

Step-by-step explanation:

We can write a proportion to find the total amount who attend university using the information given. A proportion is two equivalent ratios set equal to each other. Since 70% live on campus, then 30% live off campus and we are told that number is 1,380.

\frac{30}{100}=\frac{1380}{y}

We will cross multiply the numerator of one ratio with denominator of the other. And then solve for y.

30y=100(1380)

30y=138000

y=4600.

There are 4600 students who attend the university.

7 0
2 years ago
Tyler and Erin go out to eat . their food and beverages cost 52.25 and there is an 8% meals tax, how much is the bill? write you
drek231 [11]

Answer:

56.43

Step-by-step explanation:

52.25 + 4.18 (8% tax)

7 0
2 years ago
Help asap plssssssssssssss
olasank [31]

Answer:

÷ then +

Step-by-step explanation:

as (18÷3)+24=30 is correct same as (6÷3)+1=3

8 0
3 years ago
May someone please help me with this :)
Studentka2010 [4]

Answer:

i was taught this but i dont remember so I dont know if I can help sorry bud

8 0
3 years ago
Please help!!!!
tatyana61 [14]

Answer:

Step-by-step explanation:

From the figure attached,

If the figures shown are congruent (Equal in shape and size), length of all the sides must be equal.

Therefore, sides sides CD and GH must be equal in measures.

Distance between the two points (x_1,y_1) and (x_2,y_2) is given by,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Length of the side CD having ends C(-4, 4) and D(0, 5) will be,

CD = \sqrt{(-4-0)^2+(4-5)^2}

CD = \sqrt{(16+1)}

     = \sqrt{17}

Length of GH having ends G(0, -4) and H(4, -5) will be,

GH = \sqrt{(0-4)^2+(-4+5)^2}

      = \sqrt{16+1}

      = \sqrt{17}

Therefore, m(CD) = m(GH)

Similarly, we can prove all corresponding sides of two figures equal in measure.

This shows ABCD ≅ EFGH.

3 0
3 years ago
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