1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Molodets [167]
3 years ago
9

Ben wants to estimate the cost of dinner and a movie for himself and his friend. He knows the following information

Mathematics
1 answer:
Kamila [148]3 years ago
5 0

Answer:

B. $3100

Step-by-step explanation:

if he's going to pay for his friend. The least expensive dinner menu is $725, for him and his friend it would be $1450. Then for the movie tickets it's $8.00 each, $16.00. $1450+$16.00=$30.50. Round that to the closest whole number, $3100.

You might be interested in
Simplify -2.3f+0.9f-14-4
Setler [38]

Answer:

The Answer would be 1.4f-18

Step-by-step explanation:

-2.3f+0.9f-14-4

then you do

-1.4f-14-4

Then u would get 1.4f-18.

7 0
3 years ago
Read 2 more answers
Find the points where the line y = x - 1 intersects the circle x2 + y2 = 13
nata0808 [166]

Answer:

(-2,-3) and (3,2)

Step-by-step explanation:

sub in x-1 into y

x^2 + (x-1)^2 = 13

x^2 + (x-1)(x-1)=13

x^2 + x^2 -2x +1 = 13

2x^2 -2x-12=0

solve for x by factoring (quadratic formula, product sum etc..)

x= -2 and 3

plug in those values into y=x-1 and solve for y

3 0
3 years ago
Read 2 more answers
A music buff wants to estimate the percentage of students at a midwestern university who believe that elvis is still alive. how
gulaghasi [49]
Since we are not given any information about the proportion, we will assume the sample proportion to be 0.50

so,
p = 0.50
The Error is 10% percentage point. This means that on either side of the population proportion the error is 5% so E = 0.05
z = 1.645 (Z value for 90% confidence interval)

The margin of error for population proportion is calculated as:

E=z* \sqrt{ \frac{p(1-p)}{n} }  \\  \\ 
 \frac{E}{z} = \sqrt{ \frac{p(1-p)}{n} }  \\  \\ 
( \frac{E}{z} )^{2}= \frac{p(1-p)}{n} \\  \\ 
n= p(1-p)* (\frac{z}{E})^{2}  \\  \\ 
n=271

This means 271 students should be included in the sample
5 0
3 years ago
Line HF is tangent to circle D at point E. SEgment DE is the radius of circle D, what is true about DEF?
ivolga24 [154]

When we draw a circle with the centre at D and have a tangent HF to the circle D at point E, the angle DEF will be a right angle.

In other words angle DEF = 90 degrees

Since HF, the tangent, is a straight line, the other angle DEH should also be = 90 degrees because the straight line has an angle of 180 degrees

Therefore angle DEF = angle DEH = 90 degrees

Therefore, angle DEF is congruent to angle DEH (Option A)


3 0
2 years ago
Read 2 more answers
Please help!!! I'm really confused.
olya-2409 [2.1K]

The value of root 10 is between 3 and 3.5

4 0
3 years ago
Other questions:
  • If 1/6 of Aurora’s candy is strawberry & 4/6 are chocolate what is the friction of the candy in the box
    7·1 answer
  • Classify the AVERAGE number of students in all the math classes at Ponderosa. (Click all that apply)
    7·1 answer
  • The perimeter of a rectangular campsite is 64 cm and its area is 207 cm. Find the length and the breadth of the rectangle.
    12·2 answers
  • What keeps the temperatures on the Pacific Coast relatively moderate year-round?
    14·1 answer
  • There are 600 students in a school. The ratio of boys to girls is 3:5. How many boys and how many girls are there?
    10·1 answer
  • Which number sentence is true?
    11·1 answer
  • The weight of an object on a particular scale is 145.2 lbs. The measured weight may vary from the actual weight by at most 0.3 l
    13·1 answer
  • PLEASE HELP WILL MARK BRAINLIST!
    5·2 answers
  • Two tangents drawn to a circle from a point outside it, are equal in length.prove it.<br>​
    5·1 answer
  • 6-3/4x+1/3=1/2x+5 what number can be used to get rid of all fractions
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!