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Rzqust [24]
3 years ago
5

What is the slope of a line that is parallel to the line shown on the graph?​

Mathematics
2 answers:
SSSSS [86.1K]3 years ago
7 0

Answer:

I'm 98% sure its c. 1/4

Step-by-step explanation:

in order for a line to be parallel to another they have to be on different y intercepts but have the same slope causing them to never intersect.

the slope of the graph on the line is 1/4 because of rise over run

egoroff_w [7]3 years ago
7 0

Answer:

The slope that is parallel is 1/4

Step-by-step explanation:

Parallel line have the same slope. Hope this help!

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3 0
3 years ago
Can you solve 4 + 2/3 x = -5 in fraction form?
guapka [62]

Answer:

\frac{-27}{2} = (-13)(\frac{1}{2})

Step-by-step explanation:

The given equation is 4 + 2/3 x = -5

Taking variable on one side and constants on other side, we get

-9 = (\frac{2}{3})(x)

x = (\frac{3}{2})(-9) = \frac{-27}{2} = (-13)(\frac{1}{2}) = -13.5

The number in decimal form is given by -13.5

The number in fraction form is given as \frac{-27}{2} = (-13)(\frac{1}{2})

3 0
3 years ago
Someone please answer this lol xx
Tamiku [17]
The answer is 4 lol
3 0
3 years ago
Fred orders pictures from a photographer. Each picture costs $5.50. A one-time shipping fee of $4.25 is added to the cost of the
Alexus [3.1K]

Answer:

Fred ordered 12 pictures

Step-by-step explanation:

70.25-4.25 (one time shipping fee) =66

then you take 66 and divide it by the cost of each picture

66/5.50= 12 pictures

3 0
3 years ago
Read 2 more answers
A ferry will safely accommodate 82 tons of passenger cars. Assume that the meanweight of a passenger car is 2 tons with standard
Shalnov [3]

Answer:

The probability that the maximum safe-weight will be exceeded is <u>0.0455 or 4.55%</u>.

Step-by-step explanation:

Given:

Maximum safe-weight of 37 cars = 82 tons

∴ Maximum safe-weight of 1 car (x) = 82 ÷ 37 = 2.22 tons (Unitary method)

Mean weight of 1 car (μ) = 2 tons

Standard deviation of 37 cars = 0.8 tons

So, standard deviation of 1 car is given as:

\sigma=\frac{0.8}{\sqrt{37}}=0.13

Probability that maximum safe-weight is exceeded, P(x > 2.22) = ?

The sample is normally distributed (Assume)

Now, let us determine the z-score of the mean weight.

The z-score is given as:

z=\frac{x-\mu}{\sigma}\\\\z=\frac{2.22-2}{0.13}\\\\z=\frac{0.22}{0.13}=1.69

Now, finding P(x > 2.22) is same as finding P(z > 1.69).

From the z-score table of normal distribution curve, the value of area under the curve for z < 1.69 is 0.9545.

But we need the area under the curve for z > 1.69.

So, we subtract from the total area. Total area is 1 or 100%.

So, P(z > 1.69) = 1 - P(z < 1.69)

P(z>1.69)=1-0.9545=0.0455\ or\ 4.55\%

Therefore, the probability that the maximum safe-weight will be exceeded is 0.0455 or 4.55%.

8 0
3 years ago
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