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Nadya [2.5K]
3 years ago
10

Apply the formula of each shape to determine the

Mathematics
1 answer:
larisa86 [58]3 years ago
8 0

V (cone) = (1÷3) × (r×r×h) л cm3

3 cone = 1 cylinder (if "h" and "r" is same)

There is two cone...

1st one: (1÷3) × 3×3×5 л cm3 = 15л cm3

2nd one: (1÷3) × 3×3×8 л cm3 = 24л cm3

15 + 24 = 39л cm3

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Six hundred times 300 equals 180,000
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Please help it's urgent!Need help quick!
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charlie has 2 fair coins. he repeatedly tosses the pair of coins simultaneously (i.e., two tosses at a time), until he has seen
Serggg [28]

By using the trial method we get a total number of trials taken by Charlie to see both sides of both the coins is 4.

<h3>What is probability?</h3>

Probability is the name of the area of mathematics that deals with the examination of random events. The ratio of favorable occurrences to the total number of events is used to calculate an event's probability.

P(E) = F(E)/T (E)P(E)

It stands for the probability that an event will occur.

F(E) = Amount of favorable occurrences

Total number of trials (T(E))

Given that Charlie has 2 fair coins.

If he tosses the pair of coins simultaneously, then the number of samples can be HH, HT, TH, TT.

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7 0
11 months ago
The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 . a.
Anastasy [175]

Answer:

a) 0.073044

b) 0.75033

c) The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

Step-by-step explanation:

The overhead reach distances of adult females are normally distributed with a mean of 205.5 and a standard deviation of 8.6 .

a. Find the probability that an individual distance is greater than 218.00 cm.

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = 218

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

For x > 218

z = 218 - 205.5/8.6

z = 1.45349

Probability value from Z-Table:

P(x<218) = 0.92696

P(x>218) = 1 - P(x<218) = 0.073044

b. Find the probability that the mean for 15 randomly selected distances is greater than 204.00

When = random number of samples is given, we solve using this z score formula

z = (x-μ)/σ/√n

where

x is the raw score = 204

μ is the population mean = 205.5

σ is the population standard deviation = 8.6

n = 15

For x > 204

Hence

z = 204 - 205.5/8.6/√15

z = -0.67552

Probability value from Z-Table:

P(x<204) = 0.24967

P(x>204) = 1 - P(x<204) = 0.75033

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

The normal distribution can be used in part (b), even though the sample size does not exceed 30 because initial population size is been distributed normally , therefore, the mean of the samples will be normally distributed regardless of their size(meaning whether the sample size is less than or equal to or exceeds 30, the sample means the mean of the samples will be normally distributed regardless of their size).

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3 years ago
-10 + 10у + -3y +7<br>does anyone know the answer plz??????<br>​
PilotLPTM [1.2K]

☁️ Answer ☁️

I got: 7y - 3

Hope it helps.

Have a nice day hyung!~  ̄▽ ̄❤️

8 0
3 years ago
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