All categories

2 years ago

Apply the formula of each shape to determine the

Mathematics

1 answer:

larisa86 [58]2 years ago

8 0

V (cone) = (1÷3) × (r×r×h) л cm3

3 cone = 1 cylinder (if "h" and "r" is same)

There is two cone...

1st one: (1÷3) × 3×3×5 л cm3 = 15л cm3

2nd one: (1÷3) × 3×3×8 л cm3 = 24л cm3

15 + 24 = 39л cm3

You might be interested in

True or False? (9x - 8) - (x + 4) = 8x +12

NNADVOKAT [17]

Step-by-step explanation:

(9x-8)-(x+4)=8x+12

9x-8-x-4=8x+12

8x-12=8x+12 (no it's not)

So it's false.

Hey guys! I need help with this question urgently, so could you please help me out? Thanks in advance! Merry Christmas!

Question: brainly.com/question/19989741

3 0

3 years ago

Find the values ofx and y for the triange. x 60° 30° у

egoroff_w [7]

Answer:

x = 42, y = 36.37

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Does the data in the table represent a direct variation or an inverse variation? Write an equation to model the data in the tabl

MakcuM [25]

The equation for the direct variation is y= kx (where k is contant of variation.)

This equation represent that if x will increase then y will also increase because it's k times x.

Where the equation for indirect variation is $y=\frac{1}{k} x$

By this equation if x will increase then y will decrease and vice versa.

The given data is :

x: 2 4 8 12

y: 4 2 1 2/3

Notice as x is increasing then y is decreasing. Like x has increased from 2 to 4 then y is decresing from 4 to 2 and so on.

So, the given data represent an indirect variation.

7 0

3 years ago

[(2x)^x (2x)^2x]^1/x how do you simplify this?

Monica [59]

Note that [ (2x)^x ]^(1/x) = 2x, and that [ (2x)^(2x) ]^(1/x) = (2x)^2 = 4x^2

Multiplying these 2 results together, we get (2x)(4x^2) = 8x^3 (answer)

5 0

3 years ago

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days an

solniwko [45]

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. (a) What is the minimum pregnancy length that can be in the top 11% of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths?

Solution:

The random variable X can be defined as the pregnancy length in days.

Then, from the provided information $X\sim N(\mu=268, \sigma^{2}=12^{2})$ .

(a)

The minimum pregnancy length that can be in the top 11% of pregnancy lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

⇒ z = 1.23

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283$

Thus, the minimum pregnancy length that can be in the top 11% of pregnancy lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom 5% of pregnancy lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

⇒ z = -1.645

Compute the value of x as follows:

$z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248$

Thus, the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths is 248 days.

8 0

2 years ago