What is the mass of a 7.91cm3 piece of lead having a density of 11.34g/cm
1 answer:
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Answer:
p² -16pq + 36q²
Step-by-step explanation:
Given
(- p + 6q)²
= (- p + 6q)(-
p + 6q)
Each term in the second factor is multiplied by each term in the first factor, that is
- p(-
p + 6q) + 6q(-
p + 6q)
= p² - 8pq - 8pq + 36q² ← collect like terms
= p² - 16pq + 36q²
