A 7.5kg block is sliding down a wall with constant velocity. The coefficient of static friction between the block and the wall
1 answer:
Ok, a couple of things have to be accounted for here. First, since the block is moving relative to the wall we have to use the kinetic coefficient of friction, 0.40. The second consideration is that since the block is moving at a constant velocity, the acceleration is zero. This means, by Newton's second Law, that the net force is zero. So the force of gravity must be equal to the friction force of the wall resisting its fall. This friction force is the product of the normal force (which we are seeking) and the kinetic coefficient of friction. We can then set these two forces equal:
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Answer:
The maximum length during the motion is
Explanation:
From the question we are told that
The mass is
The vertical spring length is
The unstretched length is
The initial speed is
The new length of the spring
The spring constant k is mathematically represented as
Where F is the force applied
y is the difference in weight which is
The negative sign is because the displacement of the spring (i.e its extension occurs against the force F)
Now substituting values accordingly
The elastic potential energy is given as
where D is this the is the displacement
Since Energy is conserved the total elastic potential energy would be
Substituting value accordingly
So to obtain total length we would add the unstretched length
So we have