In order to calculate the unknown reaction force, we need to know that the sum of forces pointing down is equal the sum of the forces pointing up, so all forces will be in equilibrium.
So we have:
A 7.5kg block is sliding down a wall with constant velocity. The coefficient of static friction between the block and the wall
1 answer:
Ok, a couple of things have to be accounted for here. First, since the block is moving relative to the wall we have to use the kinetic coefficient of friction, 0.40. The second consideration is that since the block is moving at a constant velocity, the acceleration is zero. This means, by Newton's second Law, that the net force is zero. So the force of gravity must be equal to the friction force of the wall resisting its fall. This friction force is the product of the normal force (which we are seeking) and the kinetic coefficient of friction. We can then set these two forces equal:
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The collision is elastic. This means that both momentum and kinetic energy are conserved after the collision.
- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
So, the final momentum must be zero as well:
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
From which
- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is
. Therefore, the total kinetic energy before the collision is
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
(1)
But the final kinetic energy, Kf, is also
Substituting as we found in the conservation of momentum, this becomes
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write
Therefore, the two final speeds of the balls are
This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.
- Let's start with conservation of momentum. The initial momentum of the total system is the sum of the momenta of the two balls, but we should put a negative sign in front of the velocity of the second ball, because it travels in the opposite direction of ball 1. So ball 1 has mass m and speed v, while ball 2 has mass m and speed -v:
So, the final momentum must be zero as well:
Calling v1 and v2 the velocities of the two balls after the collision, the final momentum can be written as
From which
- So now let's apply conservation of kinetic energy. The kinetic energy of each ball is
the kinetic energy after the collision must be conserved, and therefore must be equal to this value:
But the final kinetic energy, Kf, is also
Substituting
we also said that Kf must be equal to the initial kinetic energy (1), therefore we can write
Therefore, the two final speeds of the balls are
This means that after the collision, the two balls have same velocity v, but they go in the opposite direction with respect to their original direction.