Question

The position of an object as a function of time is given by x = bt 2 - ct, where b = 2.0 m/s2 and c = 6.7 m/s, and x and t are in si units. what is the instantaneous velocity of the object when t = 4.1

Answer 1

Answer:

The instantaneous velocity of the object when t = 4.1 is 9.7 $\frac{m}{s}$.

Explanation:

Instantaneous velocity, v = $\frac{dx}{dt}$

x = $b t^{2} - ct$

v = $\frac{dx}{dt}$ = 2bt - c

At t = 4.1 s

v = 2 × b × 4.1 - c

b = 2.0 $\frac{m}{s^{2} }$

c = 6.7 $\frac{m}{s}$ ...(Given)

v = 2 × 2 × 4.1 - 6.7

v = 9.7 $\frac{m}{s}$

The instantaneous velocity of the object when t = 4.1 is 9.7 $\frac{m}{s}$.