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3 years ago

PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

erma4kov [3.2K]3 years ago

7 0

B)On average, boys saw the movie more than girls.

Lena [83]3 years ago

4 0

Let's go through each answer, using the line plot for reference.

A.
This is incorrect, because the boys' line plot has a few on 1, 2, 3, and it has one on 6, which makes it more spread out than the girls'.

B.
This is correct because if you find the mean/average from both data sets, you'll see the boys' is higher. (and also the girls' have more on 0 than the boys, so it's kind of obvious.) :)

The answer is B.

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)

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Answer:

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2 years ago

What is the reciprocal of 100

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3 years ago

Read 2 more answers

Drag the point A to the location indicated in each scenario to complete each statement.

Art [367]

The graph from which the position of the point A can determined following

the multiplication with a scalar is attached.

Responses:

If A is in quadrant I and is multiplied by a negative scalar, c, then c·A is in quadrant III

If A is in quadrant II and is multiplied by a positive scalar, c, then c·A is in quadrant II

If A is in quadrant II and is multiplied by a negative scalar, c, then c·A is in quadrant IV

If A is in quadrant III and is multiplied by a negative scalar, c, then c·A is in quadrant I

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, c, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

c·A = c·a + c·b·i is in the quadrant III (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar c, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

c·A = -c·a + c·b·i is in quadrant II

Multiplying A by negative scalar if A is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in quadrant IV

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying A with a negative scalar c gives;

c·A = c·a + c·b·i

c·a is positive

c·b is positive

Therefore;

c·A = c·a + c·b·i is in quadrant I

Learn more about real and imaginary numbers here;

brainly.com/question/5082885

brainly.com/question/13573157

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2 years ago