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zhenek [66]
3 years ago
6

PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
7 0
<span>B)On average, boys saw the movie more than girls.</span>
Lena [83]3 years ago
4 0
Let's go through each answer, using the line plot for reference.

A.
This is incorrect, because the boys' line plot has a few on 1, 2, 3, and it has one on 6, which makes it more spread out than the girls'. 

B.
This is correct because if you find the mean/average from both data sets, you'll see the boys' is higher. (and also the girls' have more on 0 than the boys, so it's kind of obvious.) :)

The answer is B.

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
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C) 0.75. If 6/8 of the gifts were toys, that’s 3/4 which equals 75%.
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4,3⅔,3⅓,3 common difference
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Answer:

one third

Step-by-step explanation:

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In APQR, PQ- QR. If map
Hitman42 [59]

Answer:

3x-120 = x - 30

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3(45) -120 (plug x into angle p to check your answer)

135-120

15 degrees

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Step-by-step explanation:

7 0
2 years ago
What is the reciprocal of 100
ale4655 [162]

Answer:

0.01

Steps:

The definition of "reciprocal" is simple. To find the reciprocal of any number, just calculate "1 ÷ (that number)." For a fraction, the reciprocal is just a different fraction, with the numbers "flipped" upside down (inverted). For instance, the reciprocal of 3/4 is 4/3

8 0
3 years ago
Read 2 more answers
Drag the point A to the location indicated in each scenario to complete each statement.
Art [367]

The graph from which the position of the point <em>A</em> can determined following

the multiplication with a scalar is attached.

Responses:

  • If <em>A</em> is in quadrant I and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant III</u>
  • If A is in quadrant II and is multiplied by a positive scalar, <em>c</em>, then c·A is in <u>quadrant II</u>
  • If <em>A</em> is in quadrant II and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant IV</u>
  • If <em>A</em> is in quadrant III and is multiplied by a negative scalar, <em>c</em>, then c·A is in <u>quadrant I</u>

<h3>Methods by which the above responses are obtained</h3>

Background information;

The question relates to the coordinate system with the abscissa represent the real number and the ordinate representing the imaginary number.

Solution:

If A is in quadrant I; A = a + b·i

When multiplied by a negative scalar, <em>c</em>, we get;

c·A = c·a + c·b·i

Therefore;

c·a is negative

c·b is negative

  • c·A = c·a + c·b·i is in the <u>quadrant III</u> (third quadrant)

If A is quadrant II, we have;

A = -a + b·i

When multiplied by a positive scalar <em>c</em>, we have;

c·A = c·(-a) + c·b·i = -c·a + c·b·i

-c·a is negative

c·b·i is positive

Therefore;

  • c·A = -c·a + c·b·i is in <u>quadrant II</u>

Multiplying <em>A</em> by negative scalar if <em>A</em> is in quadrant II, we have;

c·A = -c·a + c·b·i

-c·a is positive

c·b·i is negative

Therefore;

c·A = -c·a + c·b·i is in <u>quadrant IV</u>

If A is in quadrant III, we have;

A = a + b·i

a is negative

b is negative

Multiplying <em>A</em> with a negative scalar <em>c</em> gives;

c·A = c·a + c·b·i

c·a is positive

c·b  is positive

Therefore;

  • c·A = c·a + c·b·i is in<u> quadrant I</u>

Learn more about real and imaginary numbers here;

brainly.com/question/5082885

brainly.com/question/13573157

4 0
2 years ago
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