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Schach [20]
3 years ago
6

Please help! please.

Mathematics
2 answers:
tamaranim1 [39]3 years ago
5 0
A (-3, -1) 

You know this because QIII is in the bottom left corner and both numbers are negative

lesya [120]3 years ago
4 0
The answer is A, the top right is quadrant 1 top left is quadrant 2 bottom left is quadrant 3 and bottom left is quadrant 4
You might be interested in
1 2 3 4 5 6 7 8 9 10 11 12 13
Rina8888 [55]

Answer:

The mean will increase more than the median, but both will increase.

[third option listed]

Step-by-step explanation:

the <em>median </em>of a data set is the number in the middle [when listed from lowest to highest in value]

1 2 3 4 5 6 7 8 9 10 11 12 13

is the current median

let's consider what adding 12 would mean--it would mean that we move the median slightly higher [further along in the data set] because there are more numbers (but let's try this out to confirm:)

1 2 3 4 5 6 7 8 9 10 11 12 12 13

[if a median placement is shared between two numbers, the mean/average of those two numbers is taken, and that is considered to be the median]

so, 7.5 is the current median

(this is an increase of 0.5)

--

the <em>mean</em> of a data set is what we commonly refer to as the "average"

[you find this value by adding all of the numbers in the data set together and dividing by the number of terms in the data set]

1 2 3 4 5 6 7 8 9 10 11 12 13

mean of original data set:

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 [= 91]

_______________________________________

                                    13

[91 ÷ 13 = 7]

because our number is <em>greater </em>than our original mean [12 > 7], we know that the mean must increase:

[91 + 12 = 103]

[103 ÷ 14 ≈ 9.36]

[we had an increase of 2.36]

so, median increased by 0.5, mean increased by 2.36

so, both values increased, whilst the mean increased by <em>more </em>than the median [as to be expected]

you could also express this as "The mean will increase more than the median, but both will increase." [third option listed]

hope this helps!! :)

3 0
2 years ago
Following are the :
Svetlanka [38]

Answer:

Median = 241

Step-by-step explanation:

The median is the number in the middle when the variables are arranged in ascending or descending order.

The raw set of data is

177; 205; 210; 210; 232; 205; 185; 185; 178; 210; 206; 212; 184; 174; 185; 242; 188; 212; 215; 247;

241; 223; 220; 260; 245; 259; 278; 270; 280; 295; 275; 285; 290; 272; 273; 280; 285; 286; 200; 215;

185; 230; 250; 241; 190; 260; 250; 302; 265; 290; 276; 228; 265

Arranged in ascending order,

174, 177, 178, 184, 185, 185, 185, 185, 188, 190, 200, 205, 205, 206, 210, 210, 210, 212, 212, 215, 215, 220, 223, 228, 230, 232, 241, 241, 242, 245, 247, 250, 250, 259, 260, 260, 265, 265, 270, 272, 273, 275, 276, 278, 280, 280, 285, 285, 286, 290, 290, 295, 302

There are 53 variables in the data set, the median would be at the middle of the distribution, that is, at the (53 + 1)/2 position.

That gives the 27th position.

The median = variable at the 27th position when the dataset is arranged in ascending or descending order

Median = 241.

Hope this Helps!!!

6 0
3 years ago
A student spelled 92% of the words on a spelling test correctly. If the test had 24 questions, how many words did the student sp
Olegator [25]

Answer:

19

Step-by-step explanation:

3 0
3 years ago
Simply (2)/(3)a+6-(3)/(5)a-1
Bas_tet [7]

Answer:

That simplifies to \frac{1}{15}a + 5

Step-by-step explanation:

Let's simplify:

\frac{2}{3}a + 6 - \frac{3}{5}a - 1\\\\\frac{10}{15}a - \frac{9}{15}a + 6 - 1\\\\\frac{1}{15}a + 5

If you want to express that as a single fraction, you can do so by multiplying the five by 15/15, and summing the numerators.  That gives you:

\frac{a + 75}{15}

8 0
2 years ago
Which ordered pair would be the solution to the system ofequations?1.) -22.) 13.) (1, 2)4.) (1, -1)
Norma-Jean [14]

Explanation

when you have two lines in a graph, the solution is the point where the line intersect each other, so to solve this we need to find that point

so, the answer is

(1,-1)

I hope this helps you

7 0
1 year ago
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