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Arte-miy333 [17]
3 years ago
12

George and Maria decided to create a garden in their backyard. George Works on the garden every third day and Maria works on the

garden every fourth day.if thy worked on the garden today,the number of days until they work on the same day again would be
Mathematics
2 answers:
mario62 [17]3 years ago
8 0
The LCM of 3 and 4 is 12
ss7ja [257]3 years ago
7 0

Answer:

12th day

Step-by-step explanation:

We are given that George and Maria decided to create a garden in their backyard.

George works on the garden every third day  and Maria works on the garden every fourth day.

We have to find that if  they worked on the garden today ,the number until they would be work on the same day again

In order to find that day they would be work together we are finding lcm

We have to find the lcm of 3 and 4

Lcm =3\times 4=12

Hence, lcm of 3 and 4=12

Therefore, George and Maria work together on the 12th day again.

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erastova [34]

(a) The differential equation is separable, so we separate the variables and integrate:

(x+1)\dfrac{dy}{dx} = xy \implies \dfrac{dy}y = \dfrac x{x+1} \, dx = \left(1-\dfrac1{x+1}\right) \, dx

\displaystyle \frac{dy}y = \int \left(1-\frac1{x+1}\right) \, dx

\ln|y| = x - \ln|x+1| + C

When x = 0, we have y = 2, so we solve for the constant C :

\ln|2| = 0 - \ln|0 + 1| + C \implies C = \ln(2)

Then the particular solution to the DE is

\ln|y| = x - \ln|x+1| + \ln(2)

We can go on to solve explicitly for y in terms of x :

e^{\ln|y|} = e^{x - \ln|x+1| + \ln(2)} \implies \boxed{y = \dfrac{2e^x}{x+1}}

(b) The curves y = x² and y = 2x - x² intersect for

x^2 = 2x - x^2 \implies 2x^2 - 2x = 2x (x - 1) = 0 \implies x = 0 \text{ or } x = 1

and the bounded region is the set

\left\{(x,y) ~:~ 0 \le x \le 1 \text{ and } x^2 \le y \le 2x - x^2\right\}

The area of this region is

\displaystyle \int_0^1 ((2x-x^2)-x^2) \, dx = 2 \int_0^1 (x-x^2) \, dx = 2 \left(\frac{x^2}2 - \frac{x^3}3\right)\bigg|_0^1 = 2\left(\frac12 - \frac13\right) = \boxed{\frac13}

7 0
2 years ago
The goal of a toy drive is to donate more than 1000 toys. The toy drive already has collected 300 toys. How many more toys does
Brilliant_brown [7]

Answer:

Let t be the number of toys.

Since, the toy drive already has collected 300 toys

⇒ t+ 300

Also, it is given that the goal of a toy drive is to donate more than 1000 toys.

We get an inequality:

⇒t + 300 > 1000

Solve an inequality:  

t + 300 > 1000

Subtract 300 from both sides we get

t + 300 -300 > 1000-300

Simplify:

t > 700

Therefore, more than 700 toys does the toy drive need to meet its goal.

An inequality is; t + 300 > 1000 ;  t > 700




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Answer:

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Step-by-step explanation:

5 0
2 years ago
Ann increased the quantities of all the ingredients in a recipe by 60% She used 80 grams (g) of cheese How much cheese did the r
Delvig [45]

Answer:g = 50 g

Step-by-step explanation:

She used 60% more than required ⇒ she used (1+0.60)=1.60 times what was required.

x = grams required by the recipe

80 g = 1.60x

x = (80/1.60) g = 50 g

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5 2/3

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