we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
How to find the dimensions of the large rectangle?
First, we know that the large rectangle is the smaller rectangle rescaled, with a scale factor k = 4.
This means that each dimension of the smaller rectangle must be multiplied by 4 to get the correspondent dimension on the larger rectangle.
The dimensions of the smaller rectangle are:
l₁ = 12in
w₁ = 8in
Then the correspondent dimensions of the large rectangle are:
l₂ = 4*12in = 48 in
w₂= 4*8in = 32in
Now, the area of the large rectangle is given by the product between the two dimensions, we will get:
A₂ = 48in*32in = 1,536 in^2
Then, we conclude that the dimensions and area of the scaled figure are:
- l₂ = 48 in
- w₂= 32in
- A₂ = 1,536 in^2
If you want to learn more about rectangles:
brainly.com/question/17297081
#SPJ1
Step-by-step explanation:
Let y1 and y2 be (e^x)/2, and (xe^x)/2 respectively.
The Wronskian of them functions be
W = (y1y2' - y1'y2)
y1 = (e^x)/2 = y1'
y2 = (xe^x)/2
y2' = (1/2)(x + 1)e^x
W = (1/4)(x + 1)e^(2x) - (1/4)xe^(2x)
= (1/4)(x + 1 - x)e^(2x)
W = (1/4)e^(2x)
Since the Wronskian ≠ 0, we conclude that functions are linearly independent, and hence, form a set of fundamental solutions.
Answer:
No
Step-by-step explanation:
Based on the table, it would not have been from a linear function. To have a linear function, the x and y values would have to be increasing/decreasing at a constant rate.
This is the change from the first (x, y) pair to the second. Now, let's see if the next has the same change:
-7+4=-3
4-3=1
-3+4=1
3-2=1
Now, let's check the last one:
1+6=7
2-1=1
The y value is still changing by -1, but the x value has been increased by a different amount, therefore it is NOT a linear function.
Instead of a real language, I'll use pseudo code here:
var TOTAL_SCORE = 0
for(var x; i<1000; i++) {
var SCORE rand.random_integer[from 1-10];
var TOTAL SCORE = TOTAL_SCORE + SCORE;
}
print(TOTAL_SCORE);
