Factored Form:
x^2 - 4x - 5
Simplifying:
x^2 + - 4x + - 5 = 0
Reorder the terms:
- 5 + - 4x + x^2 = 0
Solving for variable " x":
Subproblem 1:
Set the factor ( - 1 + - 1x) equal to Zero and attempt to solve.
Simplifying:
- 1 + - 1x = 0
Solving:
- 1 + - 1x = 0
Move all terms containing x to the left, all other terms to the right
Add 1 to each side of equation:
- 1 + 1 + - 1x = 0 + 1
Combine Like Terms: 0 + 1 = 1
x = - 1
Divide each side by - 1
x = - 1
Simplifying: x = - 1
Subproblem 2: Set the factor (5 + - 1x) equal to Zero attempt to solve
Simplifying:
5 + - 1x = 0
Move all terms containing x to the left, all other terms to the right
Add - 5 to each side of the equation
5 + - 5 + - 1x = 0 + 5
Combine Like terms: 5 + - 5 = 0
0 + - 1x = 0 + - 5
- 1x = 0 + - 5
Combine Like Terms: 0 + - 5 = - 5
- 1x = - 5
Divide each side by - 1
x = 5
Simplifying:
x = 5
Solution:
x = { - 1, 5}
Answer when factored:
(x + 1)(x - 5)
hope that helps!!!
The shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet
<h3>What dimensions would guarantee that the garden has the greatest possible area?</h3>
The given parameter is
Perimeter, P = 520 feet
Represent the shorter side with x and the longer side with y
One side of the garden is bordered by a river:
So the perimeter is:
P = 2x + y
Substitute P = 520
2x + y = 520
Make y the subject
y = 520 - 2x
The area is
A = xy
Substitute y = 520 - 2x in A = xy
A = x(520 - 2x)
Expand
A = 520x - 2x^2
Differentiate
A' = 520 - 4x
Set to 0
520 - 4x = 0
Rewrite as:
4x= 520
Divide by 4
x= 130
Substitute x= 130 in y = 520 - 2x
y = 520 - 2 *130
Evaluate
y = 260
The area is then calculated as:
A = xy
This gives
A = 130 * 260
Evaluate
A = 33800
Hence, the shortest side is 130 feet, the longest side is 260 feet and the greatest possible area is 33800 square feet
Read more about area at:
brainly.com/question/24487155
#SPJ1
2(9x+12) + 2(3x-4)
because there are four sides, and it is a parallelogram, the opposite sides are equal. the answer is 24x+16
2+x=50
That is what I would do. I hope this helps!
