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Thepotemich [5.8K]
3 years ago
15

PLS PLS PLS HELP ME WITH THESE 2 PROBLEMS 20 POINTS

Mathematics
1 answer:
Grace [21]3 years ago
5 0

Answer: 17

Step-by-step explanation: Trust me, G!

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What is the midpoint of the segment shown below (-8,-7) (-7,-8)
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Given two points (x₁,y₁) and (x₂,y₂) the midpoint would be:
M=((x₁+x₂)/2 , (y₁+y₂)/2)

In this case, the points would be: (-8,-7) and (-7,-8); therefore:
M=((-8-7)/2 , (-7-8)/2)=(-15/2,-15/2)

Answer: C.)  (-15/2 , -15,2)
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You will need the same dataset used for problem 3 in homework 1 (the dataset obtained from the yahoo website with the company yo
stepladder [879]

Answer:

a) The probability of sampling at random a fish that is smaller in size than the value you would obtain by subtracting half the standard deviation from the average is 0.3085.

b) The probability of sampling at random a fish that is greater in size than the value you would obtain by adding half the standard deviation from the average is 0.3085.

c) The probability of sampling at random a fish that has a size between the two values is 0.383.

d) The 25th and 75 percentiles of fish size for the population using the normal distribution table is 5.69 and 5.87 respectively.

e) The probability that the average calculated will be less than the value is 0.3707.

Step-by-step explanation:

For the given data set mean (\mu) = 5.75913

Standard deviation (\sigma) = 0.172229

Variance (\sigma2) = 0.0296

Here we get is

a)

P(x < \mu - \sigma/2) = p(x < 5.673) \\\\          = 0.3085

b)

P(x < \mu + \sigma/2) = p(x < 5.845) \\\\= 0.3085

c)

P(\mu - \sigma/2 < x < \mu + \sigma/2) = p(5.673 < x < 5.845) \\\\= 0.383

d)

25th percentile:-

= 25*[(n+1)/100]th term \\\\= 5.69

75the percentile:-

= 75*[(n+1)/100]th term\\\\ = 5.87

e)  

p(x < \mu - \sigma/3) = p(x < 5.7017) \\\\= 0.3707

7 0
3 years ago
Solve: 6 yd. 9 ft 4 in. × 2
Kazeer [188]
Okay so multiply everything by 2 6yrds×2=12yrds. 9ft×2=18ft. 4in×2=8in. So the answer is: 12yrds 18ft 8in
4 0
3 years ago
Read 2 more answers
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