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Thepotemich [5.8K]
3 years ago
15

PLS PLS PLS HELP ME WITH THESE 2 PROBLEMS 20 POINTS

Mathematics
1 answer:
Grace [21]3 years ago
5 0

Answer: 17

Step-by-step explanation: Trust me, G!

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An automated egg carton loader has a 1% probability of cracking an egg, and a customer will complain if more than one egg per do
vaieri [72.5K]

Answer:

a) Binomial distribution B(n=12,p=0.01)

b) P=0.007

c) P=0.999924

d) P=0.366

Step-by-step explanation:

a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.

b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

P(k=0)=\binom{12}{0}p^0(1-p)^{12}=1*1*0.99^{12}=1*0.886=0.886\\\\P(k=1)=\binom{12}{1}p^1(1-p)^{11}=12*0.01*0.99^{11}=12*0.01*0.895=0.107

Then,

P(k>1)=1-(P(k=0)+P(k=1))=1-(0.886+0.107)=1-0.993=0.007

c) In this case, the distribution is B(1200,0.01)

P(k=0)=\binom{1200}{0}p^0(1-p)^{12}=1*1*0.99^{1200}=1* 0.000006 = 0.000006 \\\\ P(k=1)=\binom{1200}{1}p^1(1-p)^{1199}=1200*0.01*0.99^{1199}=1200*0.01* 0.000006 \\\\P(k=1)= 0.00007\\\\\\P(k\leq1)=0.000006+0.000070=0.000076\\\\\\P(k>1)=1-P(k\leq 1)=1-0.000076=0.999924

d) In this case, the distribution is B(100,0.01)

We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

P(k=0)=\binom{100}{0}p^0(1-p)^{100}=0.99^{100}=0.366

5 0
3 years ago
Find the mode of the data.<br> 41, 38, 37, 34, 37, 43, 37, 39, 41, 37
77julia77 [94]

Answer:

Step-by-step explanation:

37

8 0
3 years ago
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How to solve 243.6divided by 8
OLga [1]

Answer:

the answer is 30.45

Step-by-step explanation:

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3 years ago
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WILL GIVE BRAINLEIST DUE AT 9:45 P.M. PLS HURRY SUPER EASY. Write a division problem that has a solution of 42.
Llana [10]

Answer:

84/2=42

Step-by-step explanation:

The multiplication problem 42×2 has a product of 84, this also means that 84/2 is a dividend of 42.  This means that 84/2 is 42

5 0
3 years ago
Help!<br><br> If a sphere has a radius of 8mm, what is its volume? (Show work)
babymother [125]
The formula for the volume of a sphere is V = (4/3) * π * r³. Knowing this, we can plug in the radius:

V = \frac{4}{3} \pi *8^{3} \\ V = \frac{4}{3} \pi*512 \\ V = 2144.66

The sphere's volume is approximately 2144.66 mm^3.
7 0
3 years ago
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