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boyakko [2]
3 years ago
15

What is the slope of the line?

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
5 0

Answer:

2

Step-by-step explanation:

BartSMP [9]3 years ago
4 0
Answer: 1


Rise Over Run.
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On a circle graph, a section that represents 80% of the graph has a central angle measure of 288º.
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4 0
3 years ago
The side lengths of a rectangle are all multiplied by 5. What happens to its perimeter?
stiv31 [10]

Answer:

The perimeter is multiplied by 5.

Step-by-step explanation:

Perimeter of a rectangle:

The perimeter of a rectangle with sides l and w is given by:

P = 2(l + w)

The side lengths of a rectangle are all multiplied by 5.

This means that l = 5l, w = 5w. So

P_M = 2(5l + 5w) = 2*5(l+w) = 10(l + w)

What happens to its perimeter?

The rate is:

\frac{P_M}{P} = \frac{10(l+w)}{2(l+w)} = 5

The perimeter is multiplied by 5.

8 0
3 years ago
Find the fifth roots of 32(cos 280° + i sin 280°).
ikadub [295]
<span>Use the formula: r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ] where k = 0,1,2,3,4

</span><span>First 5th root: k = 0
r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ]
  (32)^(1/5)*[ cos( (280+360*k)/5 ) + i*sin( (280+360*k)/5 ) ]
  (32)^(1/5)*[ cos( (280+360*0)/5 ) + i*sin( (280+360*0)/5 ) ]
   2*[ cos( (280+360*0)/5 ) + i*sin( (280+360*0)/5 ) ]
  2*[ cos( (280+0)/5 ) + i*sin( (280+0)/5 ) ]
  2*[ cos( 280/5 ) + i*sin( 280/5 ) ]
  2*[ cos( 56 ) + i*sin( 56 ) ]
   -------------------------------------------------------------------
 Second 5th root: k = 1
  r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ]
  (32)^(1/5)*[ cos( (280+360*k)/5 ) + i*sin( (280+360*k)/5 ) ]
  (32)^(1/5)*[ cos( (280+360*1)/5 ) + i*sin( (280+360*1)/5 ) ]
  2*[ cos( (280+360*1)/5 ) + i*sin( (280+360*1)/5 ) ]
  2*[ cos( (280+360)/5 ) + i*sin( (280+360)/5 ) ]
  2*[ cos( 640/5 ) + i*sin( 640/5 ) ]
  2*[ cos( 128 ) + i*sin( 128 ) ]
 -------------------------------------------------------------------
 Third 5th root: k = 2
  r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ]
  (32)^(1/5)*[ cos( (280+360*k)/5 ) + i*sin( (280+360*k)/5 ) ]
  (32)^(1/5)*[ cos( (280+360*2)/5 ) + i*sin( (280+360*2)/5 ) ]
  2*[ cos( (280+360*2)/5 ) + i*sin( (280+360*2)/5 ) ]
   2*[ cos( (280+720)/5 ) + i*sin( (280+720)/5 ) ]
  2*[ cos( 1000/5 ) + i*sin( 1000/5 ) ]
  2*[ cos( 200 ) + i*sin( 200 ) ]
  -------------------------------------------------------------------
 Fourth 5th root: k = 3
  r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ]
  (32)^(1/5)*[ cos( (280+360*k)/5 ) + i*sin( (280+360*k)/5 ) ]
  (32)^(1/5)*[ cos( (280+360*3)/5 ) + i*sin( (280+360*3)/5 ) ]
  2*[ cos( (280+360*3)/5 ) + i*sin( (280+360*3)/5 ) ]
  2*[ cos( (280+1080)/5 ) + i*sin( (280+1080)/5 ) ]
  2*[ cos( 1360/5 ) + i*sin( 1360/5 ) ]
  2*[ cos( 272 ) + i*sin( 272 ) ]
   -------------------------------------------------------------------
 Fifth 5th root: k = 4
  r^(1/n)*[ cos( (theta+360*k)/n ) + i*sin( (theta+360*k)/n ) ]
  (32)^(1/5)*[ cos( (280+360*k)/5 ) + i*sin( (280+360*k)/5 ) ]
  (32)^(1/5)*[ cos( (280+360*4)/5 ) + i*sin( (280+360*4)/5 ) ]
  2*[ cos( (280+360*4)/5 ) + i*sin( (280+360*4)/5 ) ]
  2*[ cos( (280+1440)/5 ) + i*sin( (280+1440)/5 ) ]
  2*[ cos( 1720/5 ) + i*sin( 1720/5 ) ]
  2*[ cos( 344 ) + i*sin( 344 ) ]</span>
3 0
4 years ago
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