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m_a_m_a [10]
2 years ago
6

Increase £139 by 28% Give your answer rounded to 2 DP.

Mathematics
1 answer:
kotegsom [21]2 years ago
5 0

Answer:

£177.90

Step-by-step explanation:

100+28= 128%

128/100 x 139

1.28 x 139

177.92

corrected to 2dp= 177.90

or

28/100 x 139

0.28 x 139

38.92+139

177.92

177.90

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Simplify the product –8(–9) <br> A.71<br> B.74<br> C.72<br> D.70
Fittoniya [83]

Answer:

the answer is 72....

- × - = +

5 0
3 years ago
Read 2 more answers
Sam has purchased collision insurance with a $100-deductible clause, and automobile medical payments insurance in the amount of
REY [17]

The amount that the insurance company will pay is $1800.

<h3>How to illustrate the information?</h3>

It should be noted that the insurance company will pay John for the expenses of his injuries and repair of the car.

For the injury, he will get:

= $500 + ($1400 - $100)

= $500 + $2300

= $1800

Therefore, the amount is $1800.

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brainly.com/question/2141892

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3 0
2 years ago
The area of the rectangle below is __sq. units.<br> 5<br> 16
SIZIF [17.4K]

Answer:

C.

Step-by-step explanation:

To find the area of a rectangle, times the length and the breadth together. So, it would be 16×5=80. option C is 80.

4 0
3 years ago
Read 2 more answers
Each of 16 students measured the circumference of a tennis ball by four different methods, which were: A: Estimate the circumfer
almond37 [142]

Answer:

Following are the solution to the given equation:

Step-by-step explanation:

Please find the complete question in the attachment file.

In point a:

\to \mu=\frac{\sum xi}{n}

       =22.8

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{119.18}{16-1}}\\\\ =\sqrt{\frac{119.18}{15}}\\\\ = \sqrt{7.94533333}\\\\=2.8187

In point b:

\to \mu=\frac{\sum xi}{n}

       =20.6875  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{26.3375}{16-1}}\\\\=\sqrt{\frac{26.3375}{15}}\\\\ =\sqrt{1.75583333}\\\\ =1.3251

In point c:

 \to \mu=\frac{\sum xi}{n}

         =21  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{2.62}{16-1}}\\\\ =\sqrt{\frac{2.62}{15}} \\\\= \sqrt{0.174666667}\\\\=0.4179

In point d:

\to \mu=\frac{\sum xi}{n}

       =20.8375  

\to \sigma=\sqrt{\frac{\sum (xi-\mu)^2}{n-1}}

       =\sqrt{\frac{8.2975}{16-1}}\\\\ =\sqrt{\frac{8.2975}{15}} \\\\  =\sqrt{0.553166667} \\\\ =0.7438

6 0
3 years ago
Using the given zero, find one other zero of f(x). Explain the process you used to find your solution.
umka21 [38]
Complex zeroes always occurs as conjugates.
For z = a + b i conjugate is: a - b i
Another zero is : 2 + 3 i.
Verification:
2 + 3 i + 3 - 3 i = - b/a
- b = 4,  a = 1
( 2 + 3 i ) ( 2 - 3 i ) = c / a
4 - 9 i² = c / a
4 + 9 = c / a
c = 13
( x^4 - 4 x³ + 14 x² - 4 x + 13 ) : ( x² - 4 x + 13 ) = x² + 1
x² + 1 = 0
x² = -1,  x = i,  x = -i
The zeroes are: - i , i , 2 + 3 i, 2 - 3 i.
Answer: 
One another zero of f ( x ) is 2 + 3 i.
7 0
3 years ago
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