Answer:
Length= 30 in
Width= 10 in
Step-by-step explanation:
Let the width of the rectangle be x in.
Length of rectangle
= 3 (width)
= 3x
Perimeter of rectangle= 2(length) +2(width)
80= 2(3x) +2(x)
80= 6x +2x
8x= 80 <em>(</em><em>simplify</em><em>)</em>
x= 80 ÷8 <em>(</em><em>÷</em><em>8</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>
x= 10
Thus width of rectangle= 10 in
Length of rectangle
= 3(10)
= 30 in
Answer:
use the explicit rule
Step-by-step explanation:
Answer: for a sum of 7 would either be 6 and 1, 5 and 2 or 4 and 3. you can roll a double 1,2,3,4,5,6. the sum of 8 would be 2 and 6, 3 and 5 and a double 4,
Step-by-step explanation:
well the there are six sides on a die so 6 x 2 is 12 so the max sum you can get is 12. So you take 7 and you start adding up to 7, same thing for sum of 8. since there is 6 sides and a pair of dices you will roll six doubles
Answer:
The answer could be easier if you make a ratio and actual graph
Step-by-step explanation:
Let q be the number of 25 cent coins.
Let d be the number of 10 cent coins.
0.25q+0.10d= 3.95...(1)
q-d=6...(2)
(2)-> q-d= 6
q-d+d= 6+d
q= 6+d...(2a)
(2a)-> (1) 0.25q+0.10d=3.95
0.25(6+d)=0.10d= 3.95
1.95+0.25d+0.10d= 3.95
0.35d= 3.95-1.5
0.35d/0.35= 2.45/0.35
d= 7...(3)
(3)->(2) q-d= 6
q-7= 6
q=6+7
q= 13
There are 13 quarters and 7 dimes.
