Question

randall wants to mix 32 lb of nuts worth $2 per lb with some nuts worth $6 per lb to make a mixture worth $5 per lb. how many pounds of $6 nuts must use

Answer 1

Answer: 96 pounds

Step-by-step explanation:

Let x be the number of pounds of $6 nut required .

then you know the weight of the resulting mixture = (x+32)

The total cost of the mixture= $5(x+32)$

According to the question,

$5(x+32)=32\times2+6x\\\Rightarrow\ 5x+160=64+6x\\\Rightarrow\ 6x-5x=160-64\\\Rightarrow\ x=96$

Hence, Randall must use 96 pounds of $6 nuts.

Answer 2

Answer:

96 lb

Step-by-step explanation:

We are given that

Number of nuts =32 lb

Cost of 1 nut=$2

We have to find that how many pounds of $6 nuts must used.

Let x pounds be the nuts worth $6 per lb must be used.

Mixture =32+x

Cost of one lb nut in mixture =$5

According to question

$32(2)+x(6)=(32+x)\times 5$

$64+6x=160+5x$

$6x-5x=160-64$

$x=96$

Hence, 96 lb of nuts worth $6 per lb must used.