Answer:
D
Step-by-step explanation:
7 - z = 3 + z + 4 - 2z
7 - 3 - 4 = z - 2z + z
0 = 0 (Infinitely many solutions)
5(a + 4) - 15 = -5(a - 1)
5a + 20 - 15 = -5a + 5
5a + 5a = 5 - 20 + 15
10a = 40
10a/10 = 40
a = 4
(one solution)
-2d + 4d - 4 = 5 + 3(d - 3)
2d - 4 = 5 + 3d - 9
2d - 3d = 5 - 9 + 4
- d = 0
d = 0
(one solution)
-11(n - 2) + 8(n + 1) = -3(n + 10)
-11n + 22 + 8n + 8 = -3n - 30
-11n + 8n + 3n = -30 - 22 - 8
0 = -60
(no solutions)
Answer:
One leg - 15 inches
Second leg - 36 inches.
Step-by-step explanation:
One leg - x inches.
Second leg - (x + 21) inches.
Hypotenuse - 39 inches.
Using Pythagorean theorem
x² + (x + 21)² = 39²
x² + x² + 2*21x + 21² = 39²
2x² + 42x - 39² + 21² = 0
2x² + 42x - 1080 = 0
x² + 21x - 540 = 0
(x - 15)(x + 36) = 0
x = 15, x = - 36
We can use only positive value.
One leg - x inches = 15 inches
Second leg - (x + 21) inches = 15+21=36 inches.
Answer:
I think it is 3????
Step-by-step explanation:
I'm not sure but 36 / 12 = 3 so yea.
Hopefully this is right!
Answer:
The outer circle is 16 feet larger than the inner circle (68 - 52).
Step-by-step explanation:
Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:
The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).
This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).
