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tigry1 [53]
2 years ago
8

The inner circle circumference is 52 ft. the distance between the inner and the outer circle is 8ft. By how many ft is the outer

circle larger?
Mathematics
1 answer:
rjkz [21]2 years ago
8 0

Answer:

The outer circle is 16 feet larger than the inner circle (68 - 52).

Step-by-step explanation:

Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:

The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).

This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).

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f(2) This means that x is 2, so you plug in 2 for x in the equation

f(x)=\frac{1}{3} (4^x)

f(2)=\frac{1}{3}(4^2)

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f(2)=\frac{16}{3}


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Lana is the oldest of four sisters. Her youngest sister is half her age. The other two sisters are twins $2$ years younger than
vagabundo [1.1K]
Let the youngest sister be n years
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Step-by-step explanation:

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Step-by-step explanation:

Perimeter Of A Figure

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The figure shown is surrounded by line segments. We only have to add them all to find the perimeter. But we don't need each individual length to do so. We may notice the following (given all angles are right):

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