Question

The inner circle circumference is 52 ft. the distance between the inner and the outer circle is 8ft. By how many ft is the outer circle larger?

Answer 1

Answer:

The outer circle is 16 feet larger than the inner circle (68 - 52).

Step-by-step explanation:

Given that the inner circle circumference is 52 feet, and the distance between the inner and the outer circle is 8 feet, to determine by how many ft is the larger outer circle, the following calculation must be performed:

The radius of a circle is equal to half its diameter. Therefore, the radius of the inner circle is 26 feet. Thus, if the distance between the two circles is 8 feet, the radius of the outer circle is 34 feet (26 + 8). Therefore, the diameter of this circle is 68 feet (34 x 2).

This implies that the outer circle is 16 feet larger than the inner circle (68 - 52).