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Amiraneli [1.4K]
3 years ago
12

How to deactivate the brainly app?​

Computers and Technology
2 answers:
Harlamova29_29 [7]3 years ago
8 0

Answer:

you dont it says with you forever

Explanation:

galina1969 [7]3 years ago
5 0

Answer:

Don't you just uninstall it?

Explanation:

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3 years ago
Write a function named "isValidPassword" that takes in a string and returns 1 if it stores a valid password and 0 otherwise, A v
Maslowich

Answer:

Here is code in java.

import java.util.*;

import java.lang.*;

import java.io.*;

class Solution

{

public static void main (String[] args) throws java.lang.Exception

{

   try{

   //declare and initialize string variables

       String str1="password";

       String str2="Pass_word";

    //calling function to check valid password

       System.out.println("output of password is: "+isValidPassword(str1));

        System.out.println("output of Pass_word is: "+isValidPassword(str2));

   }catch(Exception ex){

       return;}

}

// functionn to check the valid password

public  static int isValidPassword(String str)

{

// variables to count the lower,upper and non character

  int i, lower_c = 0, upper_c = 0, non_c = 0;

  char ch;

  for(i=0;i<str.length();i++)

  {

      ch = str.charAt(i);

     if(ch >= 'a' && ch <= 'z')

     {//count of lower character

        lower_c++;

     }

     else if(ch >= 'A' && ch <= 'Z')

     {

   //count of upper character

        upper_c++;

     }

     else

     {

   //count of non character

        non_c++;

     }

  }

  if(lower_c > 0 && upper_c > 0 && non_c > 0) {

     return 1;

  } else {

     return 0;

  }

}

}

Explanation:

Declare and initialize two string variables.In the isValidPassword() function, pass the string parameter and then count the lower, upper and non character in the string.If string contains call the three characters then function will return 1 otherwise it will return 0 .

Output:

output of password is: 0

output of Pass_word is: 1

8 0
3 years ago
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