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Simora [160]
3 years ago
5

273.261 in word form

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
8 0
Two hundred and seventy three point two hundred and sixty one
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3 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

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  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
3 years ago
Find the distance between -2 1/2 and -5 3/4 on a number line
Elena-2011 [213]

Answer:

13/4

Step-by-step explanation:

Convert these numbers to a mixed fraction.

-5 3/4 => -23/4

-2 1/2 => -5/2

Make them have a common denominator

-5/2 => -10/4

-23/4 can stay the same.

To find the distance between the two numbers, subtract the lesser value from the greater value.

-23/4 is <u>less</u> than -10/4.

(-10 - (-23)) /4

= 13/4

Therefore the distance between -2 1/2 and -5 3/4 on a number line is 13/4.

5 0
4 years ago
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