$~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill & \$600\\ P=\textit{original amount deposited}\dotfill & \$5000\\ r=rate\to r\%\to \frac{r}{100}\\ t=years\dotfill &4 \end{cases} \\\\\\ 600=5000(\frac{r}{100})(4)\implies \cfrac{600}{5000(4)}=\cfrac{r}{100}\implies \cfrac{3}{100}=\cfrac{r}{100}\implies \boxed{3=r}$

7 0

2 years ago

in the second half of the game, the Wildcats again scored 18 points. This time, however, we don't know how many total shots were

Kobotan [32]

Lets start with the chain of 3's:

18 = 3 + 3 + 3 + 3 + 3 + 3

But, we know that

3 + 3 = 2 + 2 + 2

Sol, let's replace 3 + 3 by 2 + 2 + 2 one by one.

Hence, the possible ways of combinations are listed below:

18 = 3 + 3 + 3 + 3 + 2 + 2 + 2 (1)

18 = 3 + 3 + 2 + 2 + 2 + 2 + 2 + 2 (2)

Therefore, there are two combinations of 2- and 3- point shots that could total 18 points.

3 0

3 years ago