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asambeis [7]
2 years ago
6

A truck is bought at the price of $67,000. The price decreases at the rate of .30 every year (t). Which equation matches this ex

ponential model?
Question 3 options:

A)

f(t) = 67(.70)t

B)

f(t) = 70(67,000)t

C)

f(t) = t(.70)67,000

D)

f(t) = 67,000(.70)t
Mathematics
2 answers:
kakasveta [241]2 years ago
6 0

Answer:

f(t) = $67000(.30)^t          (Must use " ^ " to indicate exponentiation)

Step-by-step explanation:

This is an exponential function:

f(t) = $67000(.30)^t  (Must use " ^ " to indicate exponentiation)

adelina 88 [10]2 years ago
4 0

Answer:

f(t) = $67000(.30)^t          (Must use " ^ " to indicate exponentiation)

Step-by-step explanation:

This is an exponential function:

f(t) = $67000(.30)^t  (Must use " ^ " to indicate exponentiation)

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algol [13]

Answer:

<h2>w = -8</h2>

Step-by-step explanation:

Given the equation solved by Ernesto expressed as \sqrt{\dfrac{1}{2}w+8}=-2, the extraneous solution obtained by Ernesto is shown below;

\sqrt{\dfrac{1}{2}w+8}=-2\\\\square\ both \ sides \ of \ the \ equation\\(\sqrt{\dfrac{1}{2}w+8})^2=(-2)^2\\\\\dfrac{1}{2}w+8 = 4\\\\Subtract \ 8 \ from \ both \ sides\\\\\dfrac{1}{2}w+8 - 8= 4- 8\\\\\dfrac{1}{2}w= -4\\\\multiply \ both \ sides \ by \ 2\\\\\dfrac{1}{2}w*2= -4*2\\\\w = -8

Hence, the extraneous solution that Ernesto obtained is w = -8

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