I think it is 50? (Sorry if im wrong tho.)
Answer:
The percent of callers are 37.21 who are on hold.
Step-by-step explanation:
Given:
A normally distributed data.
Mean of the data,
= 5.5 mins
Standard deviation,
= 0.4 mins
We have to find the callers percentage who are on hold between 5.4 and 5.8 mins.
Lets find z-score on each raw score.
⇒
...raw score,
=
⇒ Plugging the values.
⇒
⇒
For raw score 5.5 the z score is.
⇒
⇒
Now we have to look upon the values from Z score table and arrange them in probability terms then convert it into percentages.
We have to work with P(5.4<z<5.8).
⇒ 
⇒ 
⇒
⇒
and
.<em>..from z -score table.</em>
⇒ 
⇒
To find the percentage we have to multiply with 100.
⇒ 
⇒
%
The percent of callers who are on hold between 5.4 minutes to 5.8 minutes is 37.21
Answer:
<em>D</em>
Step-by-step explanation:
Question:On Saturdays. Eve earns $14. per hour for yard work and charges an extra amount for supplies/gas money to get there. Look at the table. Choose the linear function f Eve can use to determine her pay, where x is in hours and f(x) is her pay in dollars.
Answer: <em>The answer would be D because she gets payed $14 and hour so you would plug the hours she work into the letter x</em><em>.</em>
Answer: Its a function
Step-by-step explanation:
F it rose 10% that means that it is now worth 110% of what it was a year ago. So set up an equation: 297 = 110% of x297 = 1.1 x270 = x So it was worth $270 a year ago.