All categories

3 years ago

Wanda reads 180 pages in 2 3/4 h. How many pages can she read in 5 1/2 h?

Mathematics

2 answers:

lakkis [162]3 years ago

8 0

Answer:

are there any options? if not then i think it's 360 ( sorry if i'm wrong)

Lostsunrise [7]3 years ago

6 0

Answer:

360

Step-by-step explanation:

We find Wanda's reading speed in pager per hour, which is 180/2 3/4 = 180/2.75 = 65.4545...

To find how many pages she reads in 5 1/2 hours, multiply 65.4545... by 5 1/2, or 5.5 to get 360. She reads 360 pages in 5 1/2 hours

You might be interested in

La dirección del Colegio Montes y los padres de familia están organizando un viaje cultural a Guanajuato para los alumnos de seg

notsponge [240]

Answer:

x + y = 47 (eqn 1)

x + 2y = 79 (eqn 2)

Solving the simultaneous equation,

The hotel has 15 single rooms and 32 double rooms.

Step-by-step explanation:

English Translation

The management of Colegio Montes and the parents are organizing a cultural trip to Guanajuato for second grade students and their teachers. Students will sleep in double rooms and teachers in singles. The hotel has double rooms (2 beds) and single rooms (1 bed), totaling 47 rooms and 79 beds. To confirm if they can be accommodated, they want to know how many rooms there are of each type. If "x" denotes single rooms and "y" denotes double rooms, Write the system of equations that represents the situation: Equation that represents the number of rooms (1) Equation that represents the number of beds (2)

Solution

The number of single rooms = x

The number of double rooms = y

The number of beds in single rooms = x

The number of beds in double rooms = 2y

Total number of rooms = 47

Total number of beds = 79

Sum of single and double rooms = Total number of rooms

x + y = 47 (eqn 1)

Sum of the beds in the single rooms and the beds in the double rooms = Total number of beds

x + 2y = 79 (eqn 2)

Writing the equations together

x + y = 47 (eqn 1)

x + 2y = 79 (eqn 2)

Solving the equations simultaneously,

x = 15, y = 32

Hence, the hotel has 15 single rooms and 32 double rooms.

Hope this Helps!!!

6 0

3 years ago

What does quad mean in quadratic equestion ?

Dafna11 [192]

Answer:

Though it has a degree of two and quad means four(eg:x 2-2x-3)? The Latin prefix quadri - is used to indicate the number 4,for example:quadrilateral,quadrant,etc....Quad means 4 sided square or rectangle.

3 0

4 years ago

Read 2 more answers

Suppose you graph y=5x and y=x+500 on the same coordinate plane.Which line would be steeper?Why?

solong [7]

Slope tells the steepness of the graph
y=mx+b
m=slope
so if m is bigger,t hen sloe is bigger
y=5x+0
slope is 5
y=1x+500
slope is 1

y=5x is steeper

8 0

3 years ago

Read 2 more answers

Find the critical numbers of the function f(x) = x6(x − 2)5.x = (smallest value)x = x = (largest value)(b) What does the Second

Marrrta [24]

Answer:

$a) x=0, x=\frac{12}{11}, x=2 \:$ b) The 2nd Derivative test shows us the change of sign and concavity at some point. c) At which point the concavity changes or not. This is only possible with the 2nd derivative test.

Step-by-step explanation:

a) To find the critical numbers, or critical points of:

$f(x)=x^{6}(x-2)^{5}$

1) The procedure is to calculate the 1st derivative of this function. Notice that in this case, we'll apply the <em>Product Rule</em> since there is a product of two functions.

$f(x)=x^{6}(x-2)^{5}\Rightarrow f'(x)=(f*g)'(x)\\=f'g+fg'\Rightarrow (fg)'(x)=6x^{5}(x-2)^{5}+5x^{6}(x-2)^{4} \Rightarrow 6x^{5}(x-2)^{5}+5x^{6}(x-2)^{4}=0\\f'(x)=6x^{5}(x-2)^{5}+5x^{6}(x-2)^{4}$

2) After that, set this an equation then find the values for x.

$x^{5}(x-2)^{4}[6(x-2)+5x]=0\Rightarrow x^{5}(x-2)^{4}[11x-12]=0\Rightarrow x_{1}=0\\(x-2)^{4}=0\Rightarrow \sqrt[4]{(x-2)}=\sqrt[4]{0}\Rightarrow x-2=0\Rightarrow x_{2}=2\\(11x-12)=0\Rightarrow x_{3}=\frac{12}{11}$

$x=0\:(smallest\:value)\:x_{3}=\frac{12}{11}\:x=2 (largest value)$

b) The Second Derivative Test helps us to check the sign of given critical numbers.

Rewriting f'(x) factorizing:

$f'(x)=(11x-12)(x-2)^4x^{5}$

Applying product Rule to find the 2nd Derivative, similarly to 1st derivative:

$f''(x)>0 \Rightarrow Concavity\: Up\\\\f''(x)$

$f''(x)=11\left(x-2\right)^4x^5+4\left(x-2\right)^3x^5\left(11x-12\right)+5\left(x-2\right)^4x^4\left(11x-12\right)\\f''(x)=10\left(x-2\right)^3x^4\left(11x^2-24x+12\right)$

1) Setting this to zero, as an equation:

$10\left(x-2\right)^3x^4\left(11x^2-24x+12\right)=0\\\\$

$10\left(x-2\right)^3x^4\left(11x^2-24x+12\right)=0\\(x-2)^{3}=0 \Rightarrow x_1=2\\x^{4}=0 \therefore x_2=0\\11x^{2}-24x+12=0 \Rightarrow x_3=\frac{12+2\sqrt{3}}{11}\:,x_4=\frac{12-2\sqrt{3}}{11}\cong 0.78$