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Setler [38]
3 years ago
12

How are tropical rain forests and temperate forests different?

Biology
1 answer:
Varvara68 [4.7K]3 years ago
7 0

There are two types of rainforests, tropical and temperate. Tropical rainforests are found closer to the equator where it is warm. Temperate rainforests are found near the cooler coastal areas further north or south of the equator. The tropical rainforest is a hot, moist biome where it rains all year long.

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hope this helps <3

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A large number of disease-free individuals were enrolled in a study
Nuetrik [128]

Answer:

a,Answer: Type I right censoring, censoring time = 60.

b.This is called an Interval censoring,

c.this is called Random censoring because the year in consideration was chosen at random, censoring time = 61.

d.The observations are left truncated respectively at age 30, 40, 50 and 42.

e.L\alpha \frac{S(60)}{S(30)} *\frac{S(52)-S(55)}{S(40)} *\frac{S(61)}{S(42)} *\frac{S(55)}{S(50)}

Explanation:

a) A healthy individual, enrolled in the study at age 30, never developed

breast cancer during the study.

Answer: Type I censoring, censoring time = 60.

(b) A healthy individual, enrolled in the study at age 40, was diagnosed

with breast cancer at the fifth exam after enrollment (i.e., the disease

started sometime between 12 and 15 years after enrollment).

THis is called an Interval censoring,

if the clinical exams is conducted every three years , then 3*4=12, and 3*5=15

add this to 40 years respectively, we have

censoring time = (52, 55]

c) A healthy individual, enrolled in the study at age 50, died from a

cause unrelated to the disease (i.e., not diagnosed with breast cancer

at any time during the study) at age 61.

this is called Random censoring because the year in consideration was chosen at random, censoring time = 61.

(d) An individual, enrolled in the study at age 42, moved away from

the community at age 55 and was never diagnosed with breast cancer

during the period of observation.

Random censoring, censoring time = 55.

The observations are left truncated respectively at age 30, 40, 50 and 42.

e.  Confining your attention to the four individuals described above,

write down the likelihood for this portion of the study.

L\alpha \frac{S(60)}{S(30)} *\frac{S(52)-S(55)}{S(40)} *\frac{S(61)}{S(42)} *\frac{S(55)}{S(50)}  

the above represent the likelihood

3 0
3 years ago
Ross is conducting an investigation in which he has grown three bean plants in three different pots. Each pot is similar in
Varvara68 [4.7K]

Answer:

How does the amount of water affect the growth of bean plants

Explanation:

The reason for that is because the only thing that differed in size or amount is the water. According to the question every other component, soil and amount of sunlight, are equal and the only thing not evenly distributed between the pots is the amount of water.

8 0
3 years ago
Read 2 more answers
Please Answer!! picture above
mario62 [17]

First, you need to do the multiplacation that's inside the perenthises.

Second, you will need to divide the two answers which will give you that first box.

8 0
2 years ago
Adult tickets for the school musical sold for $3.50 and student tickets sold for $2.50. On a given night, 321 tickets were sold
nalin [4]

Answer:

total amount spent on student ticket = 186($2.5)=$465.00,

Total amount spent on adult tickets = 135($3.5)=$472.50

Explanation:

cost total = student ticket price (x) + adult ticket price (321 - x)

$937.50 = (2.5)(x) + (3.5)(321 - x)

$937.50 = 2.5x + 1123.5 - 3.5x

x = 186, therefore 186 student tickets sold,  

(321-x) = 321-186 = 135, therefore 135 adult tickets were sold.

total amount spent on student ticket = 186($2.5)=$465.00,

Total amount spent on adult tickets = 135($3.5)=$472.50

So the total amount spent on tickets was  

$472.50 + $465.00 = $937.50

8 0
2 years ago
Will anyone help me?
Setler79 [48]
The high heat capacity of water prevents fish body temperatures from changing during the winter.
6 0
3 years ago
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