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3 years ago

Find the area of a trapezoid whose parallel sides measure 8.5 m and 4.5 m, and whose altitude is 6.5 m.

2 answers:

7 0

I got the answer of 42.25m²
My Work ∨
A= a+b/2 h= 8.5+4.5/2 × 6.5 = 42.25m²
/ - means the line part of a fraction
I hope I have helped

ICE Princess25 [194]3 years ago

6 0

Wassup!
Your Answer is A=42.25m²Hope this helps!:)
~Nadia~

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Solution:

Midpoint point of NY is

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$Midpoint=\left(\dfrac{-11+3}{2},\dfrac{5-3}{2}\right)$

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Product of slopes of two perpendicular lines is -1. So,

$m_1\times \dfrac{-4}{7}=-1$

$m_1=\dfrac{7}{4}$

The perpendicular bisector of NY passes through (-4,1) with slope $\dfrac{7}{4}$ . So, the equation of perpendicular bisector of NY is

$y-y_1=m_1(x-x_1)$

$y-1=\dfrac{7}{4}(x-(-4))$

$y-1=\dfrac{7}{4}(x+4)$

$y-1=\dfrac{7}{4}x+7$

Add 1 on both sides.

$y=\dfrac{7}{4}x+8$

Therefore, the equation of perpendicular bisector of NY is $y=\dfrac{7}{4}x+8$ .

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