Hello,
x^2+y^2+8x-6y+21=0
Rewritten in the form of a standard circle equation:
(x-(-4))^2+(y-3)^2=2^2
Therefore, the circle properties are:
(a,b)=(-4,3),r=2
The radius of the circle whose equation is <span>x^2 + y^2 + 8x - 6y + 21 =0 is 2.
Faith xoxo</span>
Answer:
A.-2x2+-1
Step-by-step explanation:
(-7x+5)-(2x2-8x+6)
-7x+5-2x2+8x-6 then collect like terms
-2x2-7x+8x+5-6
-2x2-x+1
If it's helpful ❤❤❤
THANK YOU
A) square
B)square based pyramid
Let us examine the speed of growth of the function. We have that the difference between successive terms is: 2, 4, 8, 16. These are powers of 2 and thus there is clearly an exponential increase in the parent function. In fact, the function can be modeled by f(x)=C+2^x where C is a constant.
We have that the new function is g(x). Translating upwards by 5 means that the new y-values are 5 units higher. Hence, we have that the pairs (x,f(x)) correspond to the pairs (x,f(x)+5) and thus the answer is that the f(x)/y-values will be increased by 5.
According to the above, we need to check the given values and see whether in some cases we have g(x)=f(x)+5; in layman's terms, we need to check whether for some x, the new y-value is bigger by 5 from the old one. This is the case only for (2,16) since the old point was (2,11).
<span>from the base line (the wall behind the hoop)
if this helps leave a thanks</span>
