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2 years ago

1. In rectangle DOTA, DO =OT.

Mathematics

1 answer:

Fittoniya [83]2 years ago

5 0

Answer:

1.) In rectangle DOTA, DO = OT. 2.) Each angle of a rectangle measures 90°

3.) The pair of opposite sides of a kite is congruent.

4.) The median of a trapezoid is parallel to each base.

5.) Each diagonal of a rhombus bisects opposite angle.

6.) In rectangle BLUE, BL divides it into two congruent triangles,

7.) Two consecutive angles of a parallelogram are supplementary angles.

8.) In a kite, the perpendicular bisector of at least one diagonal is the other diagonal.

9.) A quadrilateral is a parallelogram if one pair of opposite sides is both congruent and parallel

10.) The midsegment of a parallelogram measures one half the sums of the lengths of the bases.

Step-by-step explanation:

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2 years ago

The rectangle below has an area of 70y⁸ 30y⁶. The width of the rectangle is equal to the greatest common monomial factor of 70y⁸

Lorico [155]

Answer:

The Width of the Rectangle = $10y^6$

$\text{Length of the Rectangle}=210y^8$

Step-by-step explanation:

The area of the rectangle $=70y^8 30y^6.$

We are told that the width of the rectangle is equal to the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Let us determine the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Express each term as a product to pick out the common factors:

$70y^8 =7X10Xy^6Xy^2\\30y^6=3X10Xy^6$

In the two terms, the common terms are 10 and $y^6$ . Therefore their greatest monomial factor = $10y^6$

The Width of the Rectangle = $10y^6$

Recall: Area of a Rectangle =Length X Width

$70y^8 30y^6=Length X 10y^6\\Length =70y^8 30y^6 \div 10y^6 \\=\dfrac{70X30Xy^8Xy^6}{10y^6} =210y^8\\\text{Length of the Rectangle}=210y^8$

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3 years ago

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Solve for x a 2.2 b 5.4 c 6.5 d 7.2

Reika [66]

Answer:

Step-by-step explanation:

Given that the segment is an angle bisector then the ratio of sides and base are equal, that is

$\frac{10}{4}$ = $\frac{18}{x}$ ( cross- multiply )

10x = 72 ( divide both sides by 10 )

x = 7.2 → D

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Svetlanka [38]

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