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Tpy6a [65]
3 years ago
9

Wild

Mathematics
1 answer:
Blizzard [7]3 years ago
8 0
How many slices are all together?
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What is the tru solution to the logarithmic equation below? Log4[log4(2x)]=1
zaharov [31]

\log_4(\log_42x)=1

Take both sides as powers of 4:

4^{\log_4(\log_42x)}=4^1\implies\log_42x=4

Do it again:

4^{\log_42x}=4^4\implies2x=(2^2)^4=2^8\implies x=2^7=128

3 0
3 years ago
50 pts + Brainliest Please help <a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="462b2306">[email&#160;p
LiRa [457]
The radius of the cylinder's base is 8, so the volume of the cylinder is \pi8^218\approx3617.28 (using the approximation of \pi\approx3.14).

The sphere has radius 6, so the volume of the sphere is \dfrac43\pi6^3\approx904.32.

The volume of the shaded region is the difference between the two: 3617.28 - 904.32 = 2712.96. Rounded to the nearest integer gives an answer of 2713.
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Sidney wants to buy a charm bracelet.
attashe74 [19]

Answer:

whats the question

Step-by-step explanation:

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There is a triangle with a perimeter of 63 cm, one side of which is 21 cm. Also, one of the medians is perpendicular to one of t
NemiM [27]

Answer:

21cm; 28cm; 14cm

Step-by-step explanation:

There is no info in the problem/s  text which one of the triangle's  side is 21 cm. That is why we have to try all possible variants.

Let the triangle is ABC . Let the AK is the angle A bisector and BM is median.

Let O is AK and BM cross point.

Have a look to triangle ABM.  AO is the bisector and AOB=AOM=90 degrees (means that AO is as bisector as altitude)

=> triangle ABM is isosceles => AB=AM  (1)

1. Let AC=21   So AM=21/2=10.5 cm

So AB=10.5 cm as well.  So BC= P-AB-AC=63-21-10.5=31.5 cm

Such triangle doesn' t exist ( is impossible), because the triangle's inequality doesn't fulfill.  AB+AC>BC ( We have 21+10.5=31.5 => AB+AC=BC)

2. Let AB=21 So AM=21 and AC=42 .So  BC= P-AB-AC=63-21-42=0 cm- such triangle doesn't exist.

3. Finally let BC=21 cm. So AB+AC= 63-21=42 cm

We know (1) that AB=AM so AC=2*AB.  So AB+AC=AB+2*AB=3*AB

=>3*AB=42=> AB=14 cm => AC=2*14=28 cm.

Let check if this triangle exists ( if the triangle's inequality fulfills).

BC+AB>AC    21+14>28 - correct=> the triangle with the sides' length 21cm,14 cm, 28cm exists.

This variant is the only possible solution of the given problem.

6 0
3 years ago
Determine if 51 is rational or irrational and give a reason for your answer
Luden [163]

Answer:

irrational because the square root of 51 is irrational.

8 0
2 years ago
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