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asambeis [7]
2 years ago
15

Please help!!! its due soon :)))

Mathematics
2 answers:
adoni [48]2 years ago
6 0

Answer:

The answer my friend is B.

Dmitriy789 [7]2 years ago
5 0

Answer:

C

Step-by-step explanation:

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Please help?<br>:):):):)​
Citrus2011 [14]

Answer:

6.48%

Step-by-step explanation:

t - c = b

t = 31.93

c = 29.99

b = 31.93 - 29.99

b = 6.48%

4 0
3 years ago
Find the area of the iscoseles triangle first answer=brainliest
blsea [12.9K]

Answer:

60cm^{2}

Step-by-step explanation:

so first we need to find the height so by splitting the isosceles triangle into two right-angled triangles and then applying Pythagoras' Theorem to one of them.

h^{2} =13^{2} -5^{2}

h^{2} =169-25

h^{2} =144

h=\sqrt{144}

h=12

We now know the height of the triangle and can use this to go back and find the area of the isosceles triangle.

area of triangle = \frac{1}{2} x base x height

area of triangle = \frac{1}{2} x 10 x 12

area of triangle = 60

5 0
3 years ago
Read 2 more answers
7. Write an equation for the line that is parallel to the given line and that passes through the given point.
Vlad1618 [11]

Answer:

C. y = 1/2x - 14

Step-by-step explanation:

Find the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line parallel to  y = 1 /2 x − 8 .

y = 1 /2 x − 14                              PARALLEL

...................................................................................................................................................

Find the negative reciprocal of the slope of the original line and use the point-slope formula  y − y 1 = m ( x − x 1 )  to find the line perpendicular to  y = 1 /2 x − 8 .

y = − 2 x − 29                               PERPENDICULAR

8 0
2 years ago
If x varies directly as y, find x when y = 8.<br> x = -4 when y = 10<br> X =
timurjin [86]

Answer:

9.6

Step-by-step explanation:

I think!

6 0
2 years ago
Ayuda necesito resolver este problema con procedimiento ;)
Paraphin [41]

x^3-2x^2+x-1 is one of the prime factors of the polynomial

<h3>How to factor the expression?</h3>

The question implies that we determine one of the prime factors of the polynomial.

The polynomial is given as:

x^8 - 3x^6 + x^4 - 2x^3 - 1

Expand the polynomial by adding 0's in the form of +a - a

x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^7 - 4x^6 +x^6 + 2x^5 -2x^5- 3x^4 + 4x^4 + 2x^3 -6x^3+2x^3- x^2  -3x^2 +4x^2-2x+2x-1

Rearrange the terms

x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^8 -2x^7 + 2x^5 - 3x^4 + 2x^3 - x^2 + 2x^7 - 4x^6 + 4x^4 -6x^3+4x^2-2x+x^6-2x^5+2x^3-3x^2+2x-1

Factorize the expression

x^8 - 3x^6 + x^4 - 2x^3 - 1 = x^2(x^6-2x^5+2x^3-3x^2+2x-1) + 2x(x^6-2x^5+2x^3-3x^2+2x-1) + 1(x^6-2x^5+2x^3-3x^2+2x-1)

Factor out x^6-2x^5+2x^3-3x^2+2x-1

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x^2+2x + 1)(x^6-2x^5+2x^3-3x^2+2x-1)

Express x^2 + 2x + 1 as a perfect square

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6-2x^5+2x^3-3x^2+2x-1)

Expand the polynomial by adding 0's in the form of +a - a

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^4-x^3 +x^3-2x^3-x^2 -2x^2 +x+x - 1)

Rearrange the terms

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^6- 2x^5+x^4-x^3-x^4-2x^3-x^2+x+x^3-2x^2 +x - 1)

Factorize the expression

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3(x^3-2x^2+x-1) -x(x^3-2x^2+x-1)+1(x^3-2x^2+x-1))

Factor out x^3-2x^2+x-1

x^8 - 3x^6 + x^4 - 2x^3 - 1 = (x+1)^2(x^3 -x+1)(x^3-2x^2+x-1)

One of the factors of the above polynomial is x^3-2x^2+x-1.

This is the same as the option (c)

Hence, x^3-2x^2+x-1 is one of the prime factors of the polynomial

Read more about polynomials at:

brainly.com/question/4142886

#SPJ1

4 0
1 year ago
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