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ankoles [38]
3 years ago
14

in 9 weeks, sonjay practiced the piano for 20 hours. At this rate, how many hours would she practice in 27 weeks?​

Mathematics
2 answers:
Alex17521 [72]3 years ago
5 0

Answer:

26

Step-by-step explanation:

VLD [36.1K]3 years ago
5 0

Answer:

60 hours in 27 weeks

Step-by-step explanation:

9 times 3 is 27.

So 20 times 3 is<em><u> 60</u></em>

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A Ferris wheel rotates 9π/8 radians prior to making a stop. The total height of the Ferris wheel is 246 ft. How far around did t
WARRIOR [948]

Answer:

The ferris wheel travelled 434.717 ft.

Step-by-step explanation:

Assuming that the ferris wheel is a perfect circle, then it's height is the same as the diameter of the circle, therefore it's radius is:

radius = height/2 = 246/2 = 123 ft

The distance travelled by the ferris wheel is the same as the length of the arc created by a angle of (9pi/8). The length of an arc is given by:

length = r*(angle in radians)

length = 123*(9pi/8)

length = 434.717 ft

The ferris wheel travelled 434.717 ft.

5 0
3 years ago
Maria's math test had 25 questions she got 84% correct how many did she get wrong
inysia [295]
\frac{x}{25}=84% \\  \frac{x}{25}=.84 \\ 25( \frac{x}{25})=(.84)(25) \\ x=21
Maria got 21 correct.

Number wrong = Total - Number right
y = 25 - 21
y = 4

Maria got 4 wrong.

Hope this helps!

7 0
3 years ago
Read 2 more answers
Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t
Svet_ta [14]

Answer:

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}

[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}

[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]

Finally, the third vector of basis E is e3(t)=t^{2}

T[e3(t)]=T(t^{2})

in the equation : a2 = 1

T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}

Then

[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]

And that is the third column of [T]EE

Let's write our matrix

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

X=\left[\begin{array}{c}1&0&0\\\end{array}\right]

AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

Applying the coordinates 2,6 and -2 to the basis E we obtain

2+6t-2t^{2}

That was the original result of T[e1(t)]

8 0
3 years ago
Given that 6 x − 7 y = 22 Find y when x = − 1
kykrilka [37]

Answer

y= 4

Step-by-step explanation:

6x-7y=22

6x(-1)-7y=22

-6-7y=22

-7y=22+6

-7y=28

y=-4

7 0
3 years ago
Divide. −4 2/5÷(−5)<br> −22/25<br><br> −8/25<br><br> 8/25<br><br> 22/25
Alika [10]

−4 2/5÷(−5)

−22/25

The answer is 8/25

5 0
3 years ago
Read 2 more answers
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