Group and factor/undistribute
(x^2y^3-2y^3)+(-2x^2+4)
(y^3)(x^2-2)+(-2)(x^2-2)
see the (x^2-2) is common term so undistribute
(x^2-2)(y^2-2)
last one
The complete question in the attached figure
we know that
<span>m∠BAC = 50°
</span><span>m∠CBA = 70°
and
</span>m∠BAC+m∠CBA+m∠ACB=180°
then
m∠ACB=180-[m∠BAC+m∠CBA]---------> 180°-[50°+70°]=60°
m∠ACB=60°
remember that
BC║DE
therefore
m∠ACB=m∠DEC
m∠DEC=60°
the answer is m∠DEC=60°
Jessica’s mistake is that when isolating h from b, she multiplied b instead of dividing it on both sides. The new formula for h would be A/2b=h.
Now let’s solve. 23/2(6)=h
23/12
Approx. 1.91
Answer:
See below.
Step-by-step explanation:
I can't see any example but what I would do is first multiply both sides by 3.
4m/3 = 8
4m/3 * 3 = 8 * 3
4m = 24.
Answer:You would have to multiply
<h3>
Step-by-step 1/4× 4/4 that will equal to 4/16 and then you reduce it so your answer is 1/4 </h3>