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3 years ago

Solve for x. 32 - 9 = 72 +14

Mathematics

2 answers:

elena-14-01-66 [18.8K]3 years ago

8 0

Answer: their is no x?

Step-by-step explanation:

lawyer [7]3 years ago

4 0

Answer:

Step 1 : 9=72 & 8=56

So, in 8 & 9, values are 72 & 56 resp. The gap between the two are

72 - 56 = 16

Step 2 : 8 = 56 & 7 = 42

So, in 8 & 7, values are 56 & 42 resp. The gap between the two are

56 - 42 = 14

Step 3 : 7 = 42 & 6 = 30

So, in 7 & 6, values are 42 & 30 resp. The gap between the two are

42 - 30 = 12

Step 4 : 6 = 30 & 5 = 20

So, in 6 & 5, values are 30 & 20 resp. The gap between the two are

30 - 20 = 10

Step 5 :

From steps 1, 2, 3 & 4 its’s clear that the gap between the next sequence is 8.

4 = x

So, now

20 - x = 8

X = 20 – 8

X = 4

So, 4 = 12

Now, to find 3 = y, we know that the gap between the next sequence is 6.

So, now

12 - y = 6

Y = 12 – 6

Y = 6

So, 3=6

Step-by-step explanation:

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3 years ago

If 1/6x + 3 = 7 what is x

kotykmax [81]

Answer:

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Step-by-step explanation:

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3 years ago

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a rectangle is made by joining two squares adjacent to each other as shown below. if one squared has an area of 144 squared cent

liberstina [14]

Answer:

Hello! After reading your question I have deduced that the correct answer is 288² cm.

Step-by-step explanation:

The way I came to this conclusion was as follows:

Firstly:

If said rectangle is two squares put side by side (adjacent), then a valid assumption is that both squares are the same size.

This is because all four sides of a square have to be equal.

Thus if the two squares are joined together on one side, then all the other sides of both the squares will be the same length.

Thus both of the squares are going to be the same size, so they will have the same area.

Secondly:

If the area of one square is 144² cm then the area of the other square should also be 144² cm.

Thus if you combine the areas of both the squares, that make up the rectangle, you are left with the area of the rectangle being 288² cm.

I hope this helped!

3 0

2 years ago

Match each set of vertices with the type of triangle they form.

Andrew [12]

Answer: The calculations are done below.

Step-by-step explanation:

(i) Let the vertices be A(2,0), B(3,2) and C(5,1). Then,

$AB=\sqrt{(2-3)^2+(0-2)^2}=\sqrt{5},\\\\BC=\sqrt{(3-5)^2+(2-1)^2}=\sqrt{5},\\\\CA=\sqrt{(5-2)^2+(1-0)^2}=\sqrt{10}.$

Since, AB = BC and AB² + BC² = CA², so triangle ABC here will be an isosceles right-angled triangle.

(ii) Let the vertices be A(4,2), B(6,2) and C(5,3.73). Then,

$AB=\sqrt{(4-6)^2+(2-2)^2}=\sqrt{4}=2,\\\\BC=\sqrt{(6-5)^2+(2-3.73)^2}=\sqrt{14.3729},\\\\CA=\sqrt{(5-4)^2+(3.73-2)^2}=\sqrt{14.3729}.$

Since, BC = CA, so the triangle ABC will be an isosceles triangle.

(iii) Let the vertices be A(-5,2), B(-4,4) and C(-2,2). Then,

$AB=\sqrt{(-5+4)^2+(2-4)^2}=\sqrt{5},\\\\BC=\sqrt{(-4+2)^2+(4-2)^2}=\sqrt{8},\\\\CA=\sqrt{(-2+5)^2+(2-2)^2}=\sqrt{9}.$

Since, AB ≠ BC ≠ CA, so this will be an acute scalene triangle, because all the angles are acute.

(iv) Let the vertices be A(-3,1), B(-3,4) and C(-1,1). Then,

$AB=\sqrt{(-3+3)^2+(1-4)^2}=\sqrt{9}=3,\\\\BC=\sqrt{(-3+1)^2+(4-1)^2}=\sqrt{13},\\\\CA=\sqrt{(-1+3)^2+(1-1)^2}=\sqrt 4.$

Since AB² + CA² = BC², so this will be a right angled triangle.

(v) Let the vertices be A(-4,2), B(-2,4) and C(-1,4). Then,

$AB=\sqrt{(-4+2)^2+(2-4)^2}=\sqrt{8},\\\\BC=\sqrt{(-2+1)^2+(4-4)^2}=\sqrt{1}=1,\\\\CA=\sqrt{(-1+4)^2+(4-2)^2}=\sqrt{13}.$

Since AB ≠ BC ≠ CA, and so this will be an obtuse scalene triangle, because one angle that is opposite to CA will be obtuse.

Thus, the match is done.

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3 years ago

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