Let u = x.lnx, , w= x and t = lnx; w' =1 ; t' = 1/x
f(x) = e^(x.lnx) ; f(u) = e^(u); f'(u) = u'.e^(u)
let' find the derivative u' of u
u = w.t
u'= w't + t'w; u' = lnx + x/x = lnx+1
u' = x+1 and f'(u) = ln(x+1).e^(xlnx)
finally the derivative of f(x) =ln(x+1).e^(x.lnx) + 2x
Answer:
see graph of y = 5x - 7
Step-by-step explanation:
If graphing is the task, you should rewrite the equation in a y = ax + b form. All straight lines can be described in this form, only the a and b determine which line it is.
Your equation 5x-y=7 has the 5x on the left side, so lets move it to the right. It will get a negative sign (this is the same as subtracting 5x like you did in your picture)
5x - y = 7
-y = 7 - 5x
Now we still have the -y which should be a +y. So we multiply left and right with -1 and get:
y = -7 + 5x
If we swap the -y and 5x (we can, because they are just an addition), we get:
y = 5x - 7
Now the equation is in its "normal" form. It's like the y = ax + b with a and b chosen as a=5 and b=-7.
The normal form is handy because you can immediately see the slope is 5 and the intersection with the y-axis is at y=-7.
Answer:
$17.70
Step-by-step explanation:
Hi,
What you want to do is to find 30% of $59
First, you convert 30% into decimal form by dividing it by 100
30%=0.3
Next, you want to find 30% of 59, so what you do is you take the new decimal form and multiply it by 59
0.3×59=17.7
Ted is saving $17.70
135,634,554.....the 3 is in the 10 millions place
so the 3 is 30,000,000