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cestrela7 [59]
3 years ago
9

How do you know if 2x+3y=9xy is linear or nonlinear.

Mathematics
2 answers:
Advocard [28]3 years ago
6 0

We are given equation 2x+3y=9xy.

A linear equation is a equation that has maximum degree of the equation as 1.

Degree is the maximum power(exponent) of the variables.

If two variables are being multiplied together in a term, we can find power of the that term by adding powers of those variables.

In the given equation, on the left side we have two terms 2x and 3y, each opf the variable x, and y has power 1 and right side of the eqaution we have term 9xy. There x and y variables are being multiplied together.

So, the total power of the term would be 1+1=2.

So, the degree of the given equation would be 2.

Because degree of the given equation is not 1. Therefore, given equation is not a linear eqaution and it is a non-linear equation.

Scilla [17]3 years ago
6 0

There are several characteristics that define a linear function:

1) They are of the form y = mx + b, where m and b are real constants, or they can also have the form f (x_{1} , x_{2}, .., x_{n}) = ax_{1} + bx_{2} +, ..., + cx_{n} if the function is of several variables. Where a, b, c are real numbers.

2) The degree of the variable x is always equal to 1 or 0. That is, if there is an expression of the form x^{-1} or x ^ {2}, the function is not linear.

3) Your domain is all real numbers

4) The graph of its function in the xy plane is always a straight line.

Analyzing the aforementioned equation:

The function 2x + 3y = 9xy does not have the form described, since it has a multiplication of two variables (9xy).

The graph of its function in the xy plane is a hyperbola

Your domain is not all real numbers, because the function is not defined for x=\frac{1}{3}

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Hello :)

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Answer:

8

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3 years ago
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Zigmanuir [339]
I must confess that I was about to pass this question by, but I was captured by the respectful and dignified way in which you asked for help. 

A careful reading of the problem gives you two equations in two unknowns, which you can then solve as simultaneous equations.  Here's how it looks:

Call 'C' the price of the senior <u>C</u>itizen ticket.
Call 'S' the price of the <u>S</u>tudent ticket.

On the first night . . .    10 C  +  12 S  =  208

On the second night . . .  8C  +  3 S  =  74

Those are your two simultaneous equations. Now the idea is to multiply or divide each side of one equation in such a way that when you add or subtract it from the other equation, one of the variables will become a zero quantity ...  you'll be left with an equation in one variable, which you can easily solve. THEN, knowing the value of one variable, you can put it back into one of the original equations,and find the value of the other variable.

This all sounds more complicated than it is.   Here's how it goes:
We have . . .

10 C  +  12 S  =  208  and
8C  +  3 S  =  74

I'm going to multiply each side of the second equation by  4, and then write it under the first one:

10 C  +  12 S  =  208
32 C  +  12 S  =  296

Now, subtract the lower equation from the upper one, and you get . . .

- 22 C  +  0  =   - 88

Divide each side of this one by  -22  and you have    <em>C = $4.00</em> .

THAT's what you need, to blow the whole problem wide open.  Knowing
the value of 'C', let's substitute it into the equation for the first night:

10 C  +  12 S  =  208

10(4)  +  12 S  =  208

40  +  12 S  =  208

Subtract  40  from each side :    12 S  =  168

Divide each side by  12 :    <em>S  =</em><em>  $ 14.00 </em>.

Finally, as we look over our results, and see that Students have to pay  $14  to see the show but Seniors can get in for only  $4 , we reflect on this ... or at least I do ... and realize that getting old is not necessarily all bad.
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Another coordinate is (9,-7). This one also works.
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